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[英]Slim - How to send response with “Content-Type: application/json” header?
[英]How to post data of 'content-type application/json' to slim php rest service
我在将来自Chrome Advance rest Client的mime类型content-type application/json
数据发布到苗条框架Web服务时遇到问题。 我尝试了这些代码以发送application/json
$app->post('/register', function() use ($app) {
$app->add(new \Slim\Middleware\ContentTypes());
$params = $app->request->getBody();
$name = $params->name;
$email = $params->email;
$password = $params->password;
...});
也尝试了这个
$params = json_decode($app->request()->getBody());
var_dumb($params); //get NULL value here
得到错误
Trying to get property of non-object to this `$name = $params->name;`
请帮我如何捕获application / json格式的数据? 谢谢
根据上面的详细信息,假设您的原始JSON看起来像这样
{"name":"John Smith", "mail":"jhon@mail.com", "password":"foobar"}
您可以像这样访问您的params 数组
$app->post('/register', function () use ($app) {
$params = $app->request->getBody() ;
$params = array_filter($params);
if(!empty($params)){
$name = $params['name'];
$mail = $params['mail'];
$pass = $params['password'];
// print $name;
}
})->name("register");
或者,如果您通过Content-Type: application/x-www-form-urlencoded
在Advanced Rest客户端中发布Content-Type: application/x-www-form-urlencoded
,则可以使用$app->request->post();
访问您的数组
$app->post('/register/', function () use ($app) {
$userInfo = $app->request()->params() ;
//or
$userInfo = $app->request->post() ;
$name = $userInfo['name'];
$mail = $userInfo['email'];
$pass = $userInfo['password'];
// print $name
})->name("register");
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