繁体   English   中英

打字稿扩展不需要的接口

[英]typescript extend an interface as not required

我有两个接口;

interface ISuccessResponse {
    Success: boolean;
    Message: string;
}

interface IAppVersion extends ISuccessResponse {
    OSVersionStatus: number;
    LatestVersion: string;
}

我想将 ISuccessResponse 接口扩展为不需要; 我可以覆盖它,但还有其他选择吗?

interface IAppVersion {
    OSVersionStatus: number;
    LatestVersion: string;
    Success?: boolean;
    Message?: string;
}

我不想这样做。

有点晚了,但是 Typescript 2.1 引入了Partial<T>类型,它可以满足您的要求:

interface ISuccessResponse {
    Success: boolean;
    Message: string;
}

interface IAppVersion extends Partial<ISuccessResponse> {
    OSVersionStatus: number;
    LatestVersion: string;
}

declare const version: IAppVersion;
version.Message // Type is string | undefined

如果您希望SuccessMessage是可选的,您可以这样做:

interface IAppVersion {
    OSVersionStatus: number;
    LatestVersion: string;
    Success?: boolean;
    Message?: string;
}

不能使用extends关键字引入ISuccessResponse接口,但随后更改该接口中定义的协定(该接口表示它们是必需的)。

从 TypeScript 3.5 开始,您可以使用Omit

interface IAppVersion extends Omit<ISuccessResponse, 'Success' | 'Message'> {
  OSVersionStatus: number;
  LatestVersion: string;
  Success?: boolean;
  Message?: string;
}

您的基本接口可以将属性定义为可选:

interface ISuccessResponse {
    Success?: boolean;
    Message?: string;
}
interface IAppVersion extends ISuccessResponse {
    OSVersionStatus: number;
    LatestVersion: string;
}
class MyTestClass implements IAppVersion {
    LatestVersion: string;
    OSVersionStatus: number;
}

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM