将多个记录（行）合并为单个记录（行）

Question

我试图将多行合并为单行，我能够得到其中的一半，我尝试了多种方式来获得剩余的一半，以下是我编写的sql。 任何帮助将不胜感激。

DROP TABLE #TEST_DEPT_NAME 

CREATE TABLE #TEST_DEPT_NAME ([ID] [varchar](255) NULL,[CSN_ID] [varchar](50) NULL,[NOTE_ID] [varchar](50) NULL,[DEPARTMENT_NAME] [varchar](255) NULL,
[NOTE_CSN_ID] [varchar](50) NULL,[LINE] [varchar](50) NULL,[NOTE_TEXT] [nvarchar](max) NULL,[AUTHOR_USER_ID] [varchar](50) NULL,[AUTHOR_USER_NAME] [varchar](255) NULL,
[NOTE_TYPE_NAME] [varchar](255) NULL,[IS_ARCHIVED_YN] [varchar](255) NULL,[NOTE_STATUS_NAME] [varchar](255) NULL)

INSERT INTO #TEST_DEPT_NAME
VALUES ('123456','1234567','12345678' ,'TEST','001234' ,1 ,'NOTES_1.1' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','001234' ,1 ,'NOTES_1.1.1' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','0012345' ,2 ,'NOTES_1.2' ,'999999','TEST 1','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','00123456' ,3 ,'NOTES_1.3' ,'999999','TEST 1','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','66666' ,1 ,'NOTES_2.1' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','66666' ,2 ,'NOTES_2.2' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','66666' ,3 ,'NOTES_2.3' ,'1234','TEST','Clinic Note','N','Signed')


SELECT distinct  ID,[CSN_ID],[NOTE_ID],[DEPARTMENT_NAME],[NOTE_TYPE_NAME],[IS_ARCHIVED_YN]
,[NOTE_TEXT] =  (select ' '+ case when [NOTE_TEXT]= ''  then null else [NOTE_TEXT]end   from  #TEST_DEPT_NAME P1 
WHERE P1.[ID] = P2.[ID]AND P1.[CSN_ID] =P2.[CSN_ID] AND P1.NOTE_ID = P2.NOTE_ID AND P1.DEPARTMENT_NAME = P2.DEPARTMENT_NAME
AND P1.LINE = P2.LINE AND P1.NOTE_TYPE_NAME =P2.NOTE_TYPE_NAME AND P1.NOTE_CSN_ID = P2.NOTE_CSN_ID AND P1.IS_ARCHIVED_YN =P2.IS_ARCHIVED_YN  FOR XML PATH(''))
FROM #TEST_DEPT_NAME  P2 WHERE [ID] = '123456' 
GROUP BY ID,CSN_ID,[NOTE_ID],[DEPARTMENT_NAME],[NOTE_TYPE_NAME],[IS_ARCHIVED_YN],LINE,NOTE_CSN_ID

当我在SQL上运行时，我得到如下结果集

ID       CSN_ID  NOTE_ID    DEPARTMENT_NAME    NOTE_TEXT
123456  1234567 12345678    TEST               NOTES_1.1 NOTES_1.1.1
123456  1234567 12345678    TEST               NOTES_1.2
123456  1234567 12345678    TEST               NOTES_1.3
123456  1234567 12345678    TEST               NOTES_2.1
123456  1234567 12345678    TEST               NOTES_2.2
123456  1234567 12345678    TEST               NOTES_2.3

但我想要如下所示的结果

ID      CSN_ID  NOTE_ID     DEPARTMENT_NAME    NOTE_TEXT
123456  1234567 12345678    TEST               NOTES_1.1 NOTES_1.1.1 NOTES_1.2 NOTES_1.3
123456  1234567 12345678    TEST               NOTES_2.1 NOTES_2.2  NOTES_2.3

Answer 1

我的假设是这是foley数据，并且Note_Text的值实际上将是用户输入的长格式注释。 note_csn_id字段中的值以及Group中包含Line的值将导致查询分离出单独的“ Note_1”记录。

您的查询在#test_dept_name中产生以下结果：

ID      CSN_ID      NOTE_ID     DEPARTMENT_NAME     NOTE_CSN_ID     LINE    NOTE_TEXT       AUTHOR_USER_ID  AUTHOR_USER_NAME    NOTE_TYPE_NAME  IS_ARCHIVED_YN  NOTE_STATUS_NAME
123456  1234567     12345678    TEST                1234            1       NOTES_1.1       1234            TEST                Clinic Note     N               Signed
123456  1234567     12345678    TEST                1234            1       NOTES_1.1.1     1234            TEST                Clinic Note     N               Signed
123456  1234567     12345678    TEST                12345           2       NOTES_1.2       999999          TEST 1              Clinic Note     N               Signed
123456  1234567     12345678    TEST                123456          3       NOTES_1.3       999999          TEST 1              Clinic Note     N               Signed
123456  1234567     12345678    TEST                66666           1       NOTES_2.1       1234            TEST                Clinic Note     N               Signed
123456  1234567     12345678    TEST                66666           2       NOTES_2.2       1234            TEST                Clinic Note     N               Signed
123456  1234567     12345678    TEST                66666           3       NOTES_2.3       1234            TEST                Clinic Note     N               Signed

请注意，注释行更改时，note_csn_id也会更改。 因为您有单独的行号，所以这可能是多余的行为。 我们可以通过以下方式使查询如您所愿：

• 更改group by子句以仅考虑note_csn_id的前X个字符（通常是个坏主意，因为id字段的长度趋于增长）
• 更改note_csn_id的填充方式，使其在每个注释组中都是唯一的（如果您可以控制note_csn_id的填充方式，则更好的主意）

无论哪种情况，您都需要从子选择中删除Line上的join，并从group by子句中删除line。

如果您能够更改note_csn_id的填充方式，如下所示：

INSERT INTO #TEST_DEPT_NAME
VALUES ('123456','1234567','12345678' ,'TEST','001234' ,1 ,'NOTES_1.1' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','001234' ,1 ,'NOTES_1.1.1' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','001234' ,2 ,'NOTES_1.2' ,'999999','TEST 1','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','001234' ,3 ,'NOTES_1.3' ,'999999','TEST 1','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','66666' ,1 ,'NOTES_2.1' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','66666' ,2 ,'NOTES_2.2' ,'1234','TEST','Clinic Note','N','Signed')
,('123456','1234567','12345678' ,'TEST','66666' ,3 ,'NOTES_2.3' ,'1234','TEST','Clinic Note','N','Signed')

然后，您可以将选择更改为以下内容：

SELECT distinct  
ID,
[CSN_ID],
[NOTE_ID],
[DEPARTMENT_NAME],
[NOTE_TYPE_NAME],
[IS_ARCHIVED_YN],
[NOTE_TEXT] =  (select ' '+ case when [NOTE_TEXT]= ''  then null else [NOTE_TEXT]end   from  #TEST_DEPT_NAME P1 
WHERE P1.[ID] = P2.[ID]AND P1.[CSN_ID] =P2.[CSN_ID] AND P1.NOTE_ID = P2.NOTE_ID AND P1.DEPARTMENT_NAME = P2.DEPARTMENT_NAME
 AND P1.NOTE_TYPE_NAME =P2.NOTE_TYPE_NAME AND P1.NOTE_CSN_ID = P2.NOTE_CSN_ID AND P1.IS_ARCHIVED_YN =P2.IS_ARCHIVED_YN  FOR XML PATH(''))

FROM #TEST_DEPT_NAME  P2 WHERE [ID] = '123456' 

GROUP BY ID,CSN_ID,[NOTE_ID],[DEPARTMENT_NAME],[NOTE_TYPE_NAME],[IS_ARCHIVED_YN],NOTE_CSN_ID

并得到以下结果：

ID      CSN_ID  NOTE_ID     DEPARTMENT_NAME NOTE_TYPE_NAME  IS_ARCHIVED_YN  NOTE_TEXT
123456  1234567 12345678    TEST            Clinic Note     N                NOTES_1.1 NOTES_1.1.1 NOTES_1.2 NOTES_1.3
123456  1234567 12345678    TEST            Clinic Note     N                NOTES_2.1 NOTES_2.2 NOTES_2.3

Answer 2

您可以通过对group by使用left和stuff函数来做到这一点：

select t.ID ,t.CSN_ID,t.NOTE_ID,t.DEPARTMENT_NAME,
       STUFF((
        select ' ' + t1.NOTE_TEXT
        from #TEST_DEPT_NAME t1
        where t.ID =t1.ID  and t.CSN_ID=t1.CSN_ID and t.NOTE_ID=t1.NOTE_ID
              and t.DEPARTMENT_NAME=t1.DEPARTMENT_NAME 
              and left(t.NOTE_TEXT,8)=left(t1.NOTE_TEXT,8)
        for xml path(''), type
    ).value('.', 'varchar(max)'), 1, 1, '') NOTE_TEXT_
from #TEST_DEPT_NAME t
group by t.ID ,t.CSN_ID,t.NOTE_ID,t.DEPARTMENT_NAME,left(t.NOTE_TEXT,8)

输出：

ID      CSN_ID  NOTE_ID     DEPARTMENT_NAME NOTE_TEXT_
123456  1234567 12345678    TEST            NOTES_1.1 NOTES_1.1.1 NOTES_1.2 NOTES_1.3
123456  1234567 12345678    TEST            NOTES_2.1 NOTES_2.2 NOTES_2.3

编辑：如果您有9个以上的NOTE_TEXT我的意思是NOTES_1..,NOTES_2...,NOTES_10...,NOTES_100...那么您必须使用charindex('.',t.NOTE_TEXT)而不是上面查询中的8 ：

select t.ID ,t.CSN_ID,t.NOTE_ID,t.DEPARTMENT_NAME,
       STUFF((
        select ' ' + t1.NOTE_TEXT
        from #TEST_DEPT_NAME t1
        where t.ID =t1.ID  and t.CSN_ID=t1.CSN_ID and t.NOTE_ID=t1.NOTE_ID
              and t.DEPARTMENT_NAME=t1.DEPARTMENT_NAME 
              and left(t.NOTE_TEXT,charindex('.',t.NOTE_TEXT))
                  =left(t1.NOTE_TEXT,charindex('.',t1.NOTE_TEXT))
        for xml path(''), type
    ).value('.', 'varchar(max)'), 1, 1, '') NOTE_TEXT_
from #TEST_DEPT_NAME t
group by t.ID ,t.CSN_ID,t.NOTE_ID,t.DEPARTMENT_NAME,
         left(t.NOTE_TEXT,charindex('.',t.NOTE_TEXT))

Answer 3

我认为此查询是所需的查询：

SELECT distinct  ID,[CSN_ID],[NOTE_ID],[DEPARTMENT_NAME],[NOTE_TEXT] =
(
select ' '+ case when [NOTE_TEXT]= ''  then null else [NOTE_TEXT]end
from  #TEST_DEPT_NAME P1 
WHERE P1.[ID] = P2.[ID]
AND P1.[CSN_ID] =P2.[CSN_ID] 
AND P1.NOTE_ID = P2.NOTE_ID 
AND P1.DEPARTMENT_NAME = P2.DEPARTMENT_NAME
AND P1.NOTE_TYPE_NAME =P2.NOTE_TYPE_NAME 
AND P1.IS_ARCHIVED_YN =P2.IS_ARCHIVED_YN  
AND SUBSTRING(P1.NOTE_TEXT, 0, CHARINDEX('.', P1.NOTE_TEXT)) = SUBSTRING(P2.NOTE_TEXT, 0, CHARINDEX('.', P2.NOTE_TEXT))
FOR XML PATH('')
)
FROM #TEST_DEPT_NAME  P2 WHERE [ID] = '123456' 
GROUP BY ID,CSN_ID,[NOTE_ID],[DEPARTMENT_NAME],[NOTE_TYPE_NAME],[IS_ARCHIVED_YN],LINE,NOTE_CSN_ID,SUBSTRING([NOTE_TEXT], 0, CHARINDEX('.', [NOTE_TEXT]))

结果：

ID      CSN_ID  NOTE_ID     DEPARTMENT_NAME    NOTE_TEXT
123456  1234567 12345678    TEST               NOTES_1.1 NOTES_1.1.1 NOTES_1.2 NOTES_1.3
123456  1234567 12345678    TEST               NOTES_2.1 NOTES_2.2  NOTES_2.3