PHP实例化obj类的变量不起作用

Question

我发现了一个我不确定是PHP还是我的代码错误的问题（可能是我的），所以让我向您展示发生了什么：

<?php namespace MyApp\Conciliation;

use SimpleExcel\SimpleExcel;
use ForceUTF8\Encoding;
use MyApp\Conciliation\Gol;

class Conciliation {

    protected function equalizeFile($file, $providerName)
    {
        $type = false;
        $nfile = 'public'.$file;

        // TEST 1: the ideal aproach. not working (see error#1 bellow)
        $provider = new $providerName();

        // TEST 2: working, getting the correct response
        $provider = new Gol();

        // TEST 3: working, getting the correct response
        $provider = new MyApp\Conciliation\Gol();

        $provider->equalize($nfile);

    }

注意， $providerName = 'Gol';

error1 找不到类别'Gol'

http://inft.ly/N8Q6F4B

因此，有什么办法可以让我继续使用变量来实例化别名，就像上面一样？

---

编辑，已解决问题：工作示例

<?php namespace MyApp\Conciliation;

use SimpleExcel\SimpleExcel;
use ForceUTF8\Encoding;

class Conciliation {

    protected function equalizeFile($file, $providerName)
    {
        $type = false;
        $nfile = 'public'.$file;

        $providerName = "MyApp\\Conciliation\\".$providerName;
        $provider = new $providerName();

        $provider->equalize($nfile);
    }

Answer 1

http://php.net/manual/en/language.namespaces.dynamic.php

如果要动态调用该类，则必须使用该类的完整路径。

因此，您对equalizeFile的调用应类似于：

equalizeFile("myFile", "MyApp\\Conciliation\\Gol");