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在一个datagrid usig Linq C#WPF中联接两个表

[英]Joining two tables in one datagrid usig Linq C# WPF

我想将两个表连接到一个数据网格中。 表一: tblProjects-表二: tblEmployeeLoginDetails

在此方法中- private void FillProjectsDataGrid()我想使用以下编码填充数据网格:

            dgViewProjects.ItemsSource = DC.tblProjects.Where<tblProject>(c => c.ProjectID != null)
                .Select<tblProject, ProjectData>(m => new ProjectData()
                {
                    ProjectID = m.ProjectID,
                    Name = m.ProjectName,
                    Status = m.ProjectStatus,
                    Employee = m.EmployeeName,
                });

            dgViewProjects.ItemsSource = DC.tblEmployeeLoginDetails.Where<tblEmployeeLoginDetail>(c => c.LoginID != null)
                .Select<tblEmployeeLoginDetail, EIDData>(m => new EIDData()
                {
                    UserID = m.LoginID,
                    Name = m.EmployeeName,
                    Surname = m.EmployeeSurname,
                    Email = m.EmployeeEmailAddress,
                    Password = m.EmployeePassword,
                    Role = m.RoleID.ToString(),
                    Department = m.EmployeeDepartment,
                    IDNumber = m.EmployeeIDNumber,
                    Gender = m.EmployeeGender,
                    Date = m.EmployeeDOB.Value,
                    HomeAddress = m.EmployeeHomeAddress,
                    Telephone = m.EmployeeTelephoneNumber,
                    City = m.EmployeeCity,
                    Province = m.EmployeeProvinceCode,
                    SetImage = m.EmployeeProfilePicture
                });

对于tblProjects,我使用此类:

public struct PDData
{
    public string _project;

    public int ProjectID { get; set; }
    public string Name { get; set; }
    public string Status { get; set; }
    public string Employee { get; set; }
}

对于tblEmployeeLoginDetails,我使用此类:

public struct EIDData
{
    public string _sts;

    public int UserID { get; set; }
    public string Name { get; set; }
    public string Surname { get; set; }
    public string Email { get; set; }
    public string Password { get; set; }
    public string Role { get; set; }
    public string Department { get; set; }
    public string IDNumber { get; set; }
    public string Gender { get; set; }
    public DateTime Date { get; set; }
    public string HomeAddress { get; set; }
    public string Telephone { get; set; }
    public string City { get; set; }
    public string Province { get; set; }
    public Binary SetImage { get; set; }
}

现在,我想连接这两个表并将信息显示在一个datagrid中。 我尝试了Linq join语句,但出现此错误:

Haze.exe中发生了'System.InvalidCastException'类型的未处理异常

附加信息:无法将类型为“ System.Data.Linq.DataQuery 1[Haze.tblProject]' to type 'System.Collections.Generic.List对象1[Haze.tblProject]' to type 'System.Collections.Generic.List 1 [Haze.tblProject]”的对象。

最后是我的联接代码:

        List<tblProject> Join = (List<tblProject>)from u in DC.tblEmployeeLoginDetails
                                                  join b in DC.tblProjects
                                                  on u.LoginID equals b.ProjectID
                                                  where b.ProjectID != null
                                                  select b;

我不知道如何使用必须在一个数据网格中显示它的类将这两个表连接在一起。 如果有人有任何建议或帮助,请随时发表评论。 谢谢!

这将为您提供一个新的匿名课程,其中包含您加入的员工和项目的详细信息。 您拥有的联接仅返回项目的值

    var Join = (from u in DC.tblEmployeeLoginDetails
                                              join b in DC.tblProjects
                                              on u.LoginID equals b.ProjectID
                                              where b.ProjectID != null
                                              select new {Project=a, Employee=b}).ToList();

然后,您必须将其绑定到数据表,如下所示:

    dgViewProjects.ItemsSource = Join;

您的第一段代码将用第二段而不是添加到第二段覆盖数据源的初始设置。

你试过了吗

    List<tblProject> Join = (from u in DC.tblEmployeeLoginDetails
                                      join b in DC.tblProjects
                                      on u.LoginID equals b.ProjectID
                                      where b.ProjectID != null
                                      select b).ToList();

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