[英]javascript removing from array
你好,我的代码运行了,但是当我与星星碰撞时,它会擦除屏幕上的所有内容,但是我需要做的就是从屏幕上移除星星,但将其他所有内容都保留在原处,因为我计划为每个记分板做一个记分板后来收集的星星。
stars=[];
stars.push({
x: 420,
y: 580,
width: 5,
height: 5
});
function update() {
var score = 0; // score starts at 0
// check keys
if (keys[38] || keys[32]) {
// up arrow or space
if (!player.jumping && player.grounded) {
player.jumping = true;
player.grounded = false;
player.velY = -player.speed * 2;
}
}
if (keys[39]) {
// right arrow
if (player.velX < player.speed) {
player.velX++;
}
}
if (keys[37]) {
// left arrow
if (player.velX > -player.speed) {
player.velX--;
}
}
player.velX *= friction;
player.velY += gravity;
ctx.clearRect(0, 0, width, height);
ctx.fillStyle = "black";
ctx.beginPath();
player.grounded = false;
for (var i = 0; i < boxes.length; i++) {
ctx.rect(boxes[i].x, boxes[i].y, boxes[i].width, boxes[i].height);
var dir = colCheck(player, boxes[i]);
if (dir === "left" || dir === "right") {
player.velX = 0;
player.jumping = false;
} else if (dir === "bottom") {
player.grounded = true;
player.jumping = false;
} else if (dir === "top") {
player.velY *= -1;
}
}
for (var i = 0; i < stars.length; i++) {
ctx.rect(stars[i].x, stars[i].y, stars[i].width, stars[i].height);
var dir = colCheck(player, stars[i]);
if(dir != null)
{
delete stars[0];
//stars.splice(a);
//var resultObject = search.splice(0,1);
}
if (dir === "left" || dir === "right") {
player.velX = 0;
player.jumping = false;
} else if (dir === "bottom") {
player.grounded = true;
player.jumping = false;
} else if (dir === "top") {
player.velY *= -1;
}
}
if(player.grounded){
player.velY = 0;
}
player.x += player.velX;
player.y += player.velY;
ctx.fill();
ctx.fillStyle = "blue";
ctx.fillRect(player.x, player.y, player.width, player.height);
requestAnimationFrame(update);
}
更换
delete stars[0];
同
stars.splice(i,1);
i--;
我没有发现其他任何错误。
您需要向后遍历数组。 这是因为删除元素时数组的长度将更改(并且元素的索引将减少一),因此您当前的代码将跳过某些元素。 另外,正如deme72所说,您将要使用.splice(index, count)
从数组中删除项目。 请参阅下面的更新代码:
for (var i = stars.length - 1; i >= 0; i--) {
// Other code
stars.splice(i, 1);
}
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