[英]MySQL subquery within self join or alternative?
我正在尝试对我们的奖学金筹款俱乐部进行查询,该查询将所有门票销售返还给晚餐活动,并指出是否已购买门票的每个会员都使用她的会费(过去365天内支付)。 这将用于登录表,该表指示已购买了多少张票证以及我们是否需要让他们更新其会员资格,更新其联系信息等。我可以退回票证销售或有效的会员资格,但是我可以无法弄清楚如何将两个查询合并到一个查询中,因此我不必使用PHP数组。 希望有人可以提供帮助:
/ *以下是相关表格的摘录* /
+----------+ +--------------------+ +--------------------------+
| members | | store_transactions | | store_product_categories |
+----------+ +--------------------+ +--------------------------+
| id | | id | | id |
| last | | invoice | | category |
| first | | memberID | | officeID |
| spouse | | categoryID | | modified |
| lifetime | | productID | +--------------------------+
| email | | name |
| phone | | price | +-------------+
| created | | quantity | | pmt_methods |
+----------+ | addedBy | +-------------+
| pmtMethod | | id |
| created | | method |
+--------------------+ +-------------+
/ *第一个查询返回添加的所有Muster机票销售(通过网站进行自动交易或通过俱乐部官员进行手动交易)和PMT方法(仅RSVP,现金等)* /
SELECT member.last, member.first, member.spouse,
member.email, member.phone,
SUM(transaction.quantity) dinnerTix,
SUM(transaction.price * transaction.quantity) total,
IF (addedBy = '0' OR addedBy IS NULL, 'Website',
CONCAT_WS(' ', officer.first, officer.last))
AS addedBy, method
FROM store_transactions AS transaction
LEFT JOIN members AS member ON transaction.memberID = member.id
LEFT JOIN store_product_categories ON transaction.categoryID =
store_product_categories.id
LEFT JOIN pmt_methods ON transaction.pmtMethod = pmt_methods.id
LEFT JOIN members officer ON officer.id = addedBy
WHERE categoryID = '2'
AND year(transaction.created) = '2015'
AND (name LIKE '%member%')
GROUP BY CONCAT(member.last, '_', member.first)
ORDER BY member.last, member.first;
第一个查询返回如下内容:
+------+-------+--------+-------------+--------------+---
| last | first | spouse | email | phone |
+------+-------+--------+-------------+--------------+---
| Doe | John | Jane | abc@abc.com | 123-456-7890 |
+------+-------+--------+-------------+--------------+---
---+-----------+--------+-----------+--------+
| dinnerTix | total | addedBy | method |
---+-----------+--------+-----------+--------+
| 5 | 150.00 | President | cash |
---+-----------+--------+-----------+--------+
/ *此第二个查询返回所有活动成员,在上一次会员购买时加1年以显示年度会员到期* /
SELECT last, first,
DATE_FORMAT(ADDDATE(store_transactions.created, INTERVAL 1 YEAR),
'%M %e, %Y') AS expires
FROM store_transactions
LEFT JOIN members ON store_transactions.memberID = members.id
WHERE store_transactions.created >= SUBDATE(CURDATE(), INTERVAL 1
YEAR) AND categoryID = 1 OR lifetime = 'Y'
GROUP BY members.id
ORDER BY members.last, members.first;
第二个查询返回如下内容:
+------+-------+-------------+
| last | first | expires |
+------+-------+-------------+
| Doe | John | May 3, 2015 |
+------+-------+-------------+
我认为合并两个查询将很简单,因此第二个查询中返回的到期日期将附加到第一个查询结果的每一行。 不幸的是,我在这里追尾,所以任何帮助将不胜感激! 这是我第一次尝试使用自联接和表别名,因此我试图在不破坏过去8年运行良好的站点的情况下扩大视野! 谢谢!!
应该很容易。 假设Q1
=您的第一个查询,而Q2
=您的第二个查询。 它应该很简单:
select q1.*, q2.expires
from (Q1) q1
inner join (Q2) q2
on q1.last = q2.last and q1.first = q2.first
只需复制和粘贴您的第一个查询,其中Q1
是,括号里面,做同样的你的第二个查询到Q2
当然,如果有两个同名的人,这会中断,在这种情况下,最好在两个查询中都包含id
字段,然后再加入。
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