Java中带有数据文件的2D数组

Question

谁能帮助我使用2D数组重写此代码，以遍历并显示选择吗？

以下是测验型游戏。 我有一个文本文件，程序会读取此数据，因此，首先是问题，然后是4个答案选择，然后是答案（我在文件中有20个问题）：

1) What is 1+2 = ...?
a) 2
b) 3
c) 0
d) 1
b
...

这是代码：

import java.io.File;
import java.util.Scanner;
import javax.swing.JOptionPane;

public class GameQuiz
{
    public static void main(String[] args) {
        String[] data = new String[120];
        String question = "";
        int count = 0;
        try{
            Scanner inFile = new Scanner(new File("questions.txt"));
            while (inFile.hasNext()){
                data[count] = inFile.nextLine();
                count++;
            }
            inFile.close();
        }catch(Exception e){
            e.printStackTrace();
        }

        int choice = 0, numCorrect = 0, i = 0;
        char correctAnswer = ' ', correct = ' ';
        String answer= "";
        String answerChoices[] = {"a", "b", "c", "d"};
        for (int j = 0; j < 20; j++)
        {
            answer = "";
            for (i = 0; i < 5; i++)
            {
                answer += data[i+(j*6)] + "\n";
            }
            correctAnswer = data[i+(j*6)].charAt(0);

            choice = JOptionPane.showOptionDialog(null, answer, "Quiz Game",
                    0, 3, null, answerChoices, null);


            if (choice == 0) correct = 'a';
            if (choice == 1) correct = 'b';
            if (choice == 2) correct = 'c';
            if (choice == 3) correct = 'd';

            if (correct == correctAnswer)
            {
                numCorrect ++;
                JOptionPane.showMessageDialog(null, "Correct!");
            }
            else JOptionPane.showMessageDialog(null, "Sorry.\n"+
                    "The correct answer was "+correctAnswer);
        }
        JOptionPane.showMessageDialog(null, "You have "+numCorrect+"/20 correct answers.");
    }
}

Answer 1

您不需要太多更改：

    while (inFile.hasNext()){
         for(int i = 0; i <20; i++){
              for(int j = 0;j <6; j++){
                   data[i][j] = inFile.nextLine();
                   count++;
              }
         }
    }

和：

    for (i = 0; i < 5; i++){
          answer += data[j][i] + "\n";
    }
    correctAnswer = data[j][i].charAt(0);

它应该工作正常。 但是，您应该按照注释中的建议考虑更好的解决方案。 这不是最有效的方法。

编辑：此外，您还需要更改data []声明：

String[][] data = new String[20][6];