[英]Mysqli_query SELECT returns false
我目前正在尝试根据学号和密码获取某个用户...问题是 mysqli_query 不断返回 false(?) 语句。 虽然我通过在 PHPMyAdmin 中测试来检查查询。 这是我的查询:
$number = $_POST['number'];
$password = $_POST['password'];
$sql = "SELECT studentNumber FROM student where studentNumber = '$number'" ;
$result = mysqli_query($conn, $sql) or die(mysqli_error());;
if(!$result){
echo "FAIL";
}
else if($result > 0){
header("register.html");
}else{
$sql = "INSERT INTO 'sampleDB'.'student'('userID', 'studentNumber', 'password') VALUES ('', $number, $password)";
header("login.html");
}
这是我的代码连接部分:
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
您应该通过num_rows
检查查询结果确实产生了多少行,然后如果为零则进行一些插入。
请注意,列引号实际上是反引号而不是单引号:
$number = $_POST['number'];
$password = $_POST['password'];
// checking
$sql = 'SELECT studentNumber FROM student WHERE studentNumber = ?';
$select = $conn->prepare($sql);
$select->bind_param('s', $number);
$select->execute();
// if there is no student number, register
if($select->num_rows > 0) {
// there is student number found
header('Location: index.html'); exit;
} else {
// there is NO student number found
$sql = 'INSERT INTO sampleDB.student(userID, studentNumber, password) VALUES (NULL, ?, ?)';
$insert = $conn->prepare($sql);
$insert->bind_param('ss', $number, $password);
$insert->execute();
header('Location: login.html');
}
旁注:您的连接代码似乎在问题上被截断了。 不要忘记将您的数据库名称添加到连接中:
$conn = new mysqli($servername, $username, $password, $database_name);
$sql = "SELECT studentNumber FROM student where studentNumber = '$number'" ;
改成
$sql = "SELECT studentNumber FROM student where studentNumber = '".$number."'" ;
首先获取结果并在您的条件下使用它。
$result2 = mysql_fetch_array($result);
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