[英]PHP mysqli_stmt_bind_result with mysqli union
因此,我试图创建一个UNION query
,以便可以从两个表(相同的数据库)中获取数据,稍后再尝试使用mysqli_bind_result()
拉取该数据,但出现错误:
mysqli_stmt_bind_result():绑定变量数与数字不匹配
这是我的代码:
$sql = mysqli_stmt_init($con);
if(mysqli_stmt_prepare($sql, "(SELECT `naslov`, `id_lang` FROM `naslovi` WHERE `id_vijesti` = ?) UNION ALL (SELECT `text`, `id_lang` FROM `tekstovi` WHERE `id_vijesti` = ?)")) {
mysqli_stmt_bind_param($sql, "ii", $id, $id);
mysqli_stmt_execute($sql);
mysqli_stmt_bind_result($sql, $naslov, $id_lang1, $text, $id_lang2);
$vijest = array();
while(mysqli_stmt_fetch($sql)) {
echo $naslov;
if($id_lang1 == $id_lang2) {
$vijest[] = array($naslov, $text, $id_lang1);
}
}
mysqli_stmt_close($sql);
该错误表明变量数量不匹配。 UNION查询合并内部查询中的所有列。
我认为您正在这里寻找JOIN查询。 看一下此页面: http : //www.sitepoint.com/understanding-sql-joins-mysql-database/
编辑:添加了一个示例
"SELECT
`naslovi`.`naslov`, `naslovi`.`id_lang`, `tekstovi`.`text`, `tekstovi`.`id_lang` AS tekstovi_id_lang
FROM `naslovi` JOIN `tekstovi`
ON `naslovi`.`id_vijesti` = `tekstovi`.`id_vijesti`
WHERE `naslovi`.`id_vijesti` = ?"
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