[英]2d array rows and cols Backwards ? -Java
考虑到这一点
private int[][] goal = {{1,5,9,13}, {2,6,10,14}, {3,7,11,15},{4,8,12,0}};
public FifteenPuzzle1 (int[][] initialGrid) {
if (initialGrid == null)
throw new NullPointerException("null grid");
if (initialGrid.length != size)
throw new IllegalArgumentException("Grid does not have " + size + " rows");
for (int i = 0; i < size; i++) {
if (initialGrid[i] == null)
throw new NullPointerException("null row");
else if (initialGrid[i].length != size)
throw new IllegalArgumentException("Grid is not square");
}
grid = initialGrid;
boolean[] found = new boolean[size * size];
for (int i = 0; i < size; i++) {
for (int j = 0; j < size; j++) {
if (grid[i][j] < 0)
throw new IllegalArgumentException("Negative square found: " + grid[i][j]);
else if (grid[i][j] > size * size - 1)
throw new IllegalArgumentException("Overflow square found: " + grid[i][j]);
else if (found[grid[i][j]])
throw new IllegalArgumentException("Grid has multiple " + grid[i][j] + "s");
else {
found[grid[i][j]] = true;
if (grid[i][j] == 0) {
xspace = i; yspace = j;
}
}
}
}
sc = new SimpleCanvas("Fifteen Puzzle", gridsize, gridsize, bgColor);
sc.addMouseListener(this);
drawGrid();
}
当将目标传递给构造函数时,我希望最上面一行读取的是1,5,9,13而不是当前所做的1,2,3,4。 我想念什么?
执行此操作时:
for (int i = 0; i < x; i++) {
for (int j = 0; j < y; j++) {
...
}
}
该数组首先沿j
轴填充,因此得到1,2,3,4,因为它们是输入位置0处的值。 要以您想要的方式获得它,请分配grid[j][i]
而不是[i][j]
要么
转过输入矩阵
要么
改变外循环
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