繁体   English   中英

如何快速绘制一个简单的圆角矩形(圆角)

[英]How to draw a simple rounded rect in swift (rounded corners)

我设法画了一个矩形 :-) 但我不知道如何画一个圆形的矩形。

有人可以用以下代码帮助我如何舍入矩形吗?

let canvas = UIGraphicsGetCurrentContext()
rec = CGRectMake(0, 0, 40, 40);

//var maskPath = UIBezierPath(roundedRect: rec, byRoundingCorners: .BottomLeft | .BottomRight, cornerRadii: CGSize(width: 3, height: 3))

CGContextAddRect(canvas, rec);
CGContextFillPath(canvas);

//将此代码放在你的drawRect中

目标-C

 - (void)drawRect:(CGRect)rect
{

CGContextRef ctx = UIGraphicsGetCurrentContext();
CGContextSaveGState(ctx);


 CGPathRef clippath = [UIBezierPath bezierPathWithRoundedRect:CGRectMake(x,y, width, height) cornerRadius:6].CGPath;
CGContextAddPath(ctx, clippath);

CGContextSetFillColorWithColor(ctx, self.color.CGColor);

CGContextClosePath(ctx);
CGContextFillPath(ctx);

[self.color set];


[_path closePath]; // Implicitly does a line between p4 and p1
[_path fill]; // If you want it filled, or...
[_path stroke]; // ...if you want to draw the outline.
CGContextRestoreGState(ctx);
}

斯威夫特 3

func drawRect(rect : CGRect)
{
// Size of rounded rectangle
let rectWidth = rect.width
let rectHeight = rect.height

// Find center of actual frame to set rectangle in middle
let xf:CGFloat = (self.frame.width  - rectWidth)  / 2
let yf:CGFloat = (self.frame.height - rectHeight) / 2

let ctx: CGContext = UIGraphicsGetCurrentContext()!
ctx.saveGState()

let rect = CGRect(x: xf, y: yf, width: rectWidth, height: rectHeight)
let clipPath: CGPath = UIBezierPath(roundedRect: rect, cornerRadius: rectCornerRadius).cgPath

ctx.addPath(clipPath)
ctx.setFillColor(rectBgColor.cgColor)




ctx.closePath()
ctx.fillPath()
ctx.restoreGState()

}

如何使用 BezierPath 创建圆角矩形

 var roundRect = UIBezierPath(roundedRect: <CGRect>, byRoundingCorners: <UIRectCorner>, cornerRadii: <CGSize>)

或者以值为例:

var roundRect = UIBezierPath(roundedRect: CGRectMake(0, 0, 100, 100), byRoundingCorners:.AllCorners, cornerRadii: CGSizeMake(16.f, 16.f))

斯威夫特 5

var roundRect = UIBezierPath(roundedRect: CGRect(x: 0, y: 0, width: 100, height: 100), byRoundingCorners:.allCorners, cornerRadii: CGSize(width: 16.0, height: 16.0))

@mukuSwift 4.x+ 中的回答:

override func draw(_ rect: CGRect) {
  super.draw(rect)

  let clipPath = UIBezierPath(roundedRect: rect, cornerRadius: 6.0).cgPath

  let ctx = UIGraphicsGetCurrentContext()!
  ctx.addPath(clipPath)
  ctx.setFillColor(UIColor.red.cgColor)

  ctx.closePath()
  ctx.fillPath()
}

斯威夫特 5、4

iOS 11

override func draw(_ rect: CGRect) {
  super.draw(rect)

  guard let context = UIGraphicsGetCurrentContext() else { return }

  context.saveGState()
  defer { context.restoreGState() }

  let path = UIBezierPath(
    roundedRect: rect,
    byRoundingCorners: [.topLeft, .topRight],
    cornerRadii: CGSize(width: 4, height: 4)
  )

  context.addPath(path.cgPath)
  context.closePath()

  context.setStrokeColor(UIColor.red.cgColor)
  context.strokePath()
}

SWIFT 3.x + 4.0我已经修改了 Swift 3 的示例并添加了几行来将矩形集中在 UIView 中

func roundRect()
{
    // Size of rounded rectangle
    let rectWidth:CGFloat = 100
    let rectHeight:CGFloat = 80

    // Find center of actual frame to set rectangle in middle
    let xf:CGFloat = (self.frame.width  - rectWidth)  / 2
    let yf:CGFloat = (self.frame.height - rectHeight) / 2

    let ctx: CGContext = UIGraphicsGetCurrentContext()!
    ctx.saveGState()

    let rect = CGRect(x: xf, y: yf, width: rectWidth, height: rectHeight)
    let clipPath: CGPath = UIBezierPath(roundedRect: rect, cornerRadius: rectCornerRadius).cgPath

    ctx.addPath(clipPath)
    ctx.setFillColor(rectBgColor.cgColor)




    ctx.closePath()
    ctx.fillPath()
    ctx.restoreGState()

}

带屏幕截图的完整代码可在: http : //lab.dejaworks.com/uiview-with-rounded-background-designable-in-storyboard/

具有圆角矩形背景的可设计 UIView

override func draw(_ rect: CGRect) {

    let bezierPath = UIBezierPath(roundedRect: CGRect(x: 0, y: 0, width: 40.0, height: 40.0), cornerRadius: 3.0)
    UIColor.yellow.setFill()
    bezierPath.fill()

}

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM