如何使用javax.xml.xpath在xml标记属性内的值中更改内容值？

Question

使用JAVA和javax.xml.xpath的库（作为XpathFactory和XpathExpression），考虑到XPath是：如何更改标记“值= 6”的xml标记属性“ 6”：

"number(/suite/test/classes/class/methods/include/parameter[1]/@value)"

xPathFactory可以识别xpath函数吗？ 还是有其他想法？

以下XML进行更改：

<?xml version="1.0" encoding="UTF-8"?>

<suite name="Test1" Alowinterrupt="true">
    <test name="testscale">
        <classes>
            <class name="test">
                <methods>
                <include name="poweronoff">
                <parameter name="ScaleTesting" value="6"/>
                </include>
                </methods>
            </class>
        </classes>
    </test>
</suite>

Answer 1

您可以使用DOM解析器在Java中修改XML文件。

// parse the XML as a W3C Document
DocumentBuilder builder = DocumentBuilderFactory.newInstance()
        .newDocumentBuilder();
Document document = builder.parse(new File(xmlFilePath));

XPath xpath = XPathFactory.newInstance().newXPath();
String expression = "/suite/test/classes/class/methods/include/parameter[1]";
Node parameter = (Node) xpath.evaluate(expression, document,
        XPathConstants.NODE);

// update parameter , set the value to 10
NamedNodeMap attribute = parameter.getAttributes();
Node nodeAttr = attribute.getNamedItem("value");

System.out.println("Old id value: " + nodeAttr.getTextContent());
Transformer transformer = TransformerFactory.newInstance()
        .newTransformer();
Result output = new StreamResult(new File(xmlFilePath));
nodeAttr.setTextContent("2");
Source input = new DOMSource(document);
transformer.transform(input, output);
System.out.println("New id value: " + nodeAttr.getTextContent());

输出：

Old parameter value: 6
New parameter value: 2