[英]How to route in Mule ESB using request path
您好,我正在尝试在流中添加路由器,以便我可以重用我的代码并避免重复。
我通常为每个请求路径执行一个流程,例如:
HTTP LISTENER =本地主机:8080 / mule1 HTTP LISTENER =本地主机:8080 / mule2
我想知道是否可以使用请求路径通过路由器/选择器连接器进行路由。 我无法执行此操作,因为它告诉我/的监听器
这是我的代码:
<flow name="Tickets">
<http:listener config-ref="HTTP_Listener_Configuration" path="/" doc:name="HTTP"/>
<logger message="#[message.inboundProperties.'http.listener.path']" level="INFO" doc:name="Logger"/>
<choice doc:name="Choice">
<when expression="#[message.inboundProperties.'http.request.path' == "/getTicketByTicketCode"]">
<set-payload value="#[message.inboundProperties.'http.query.params'.ticketcode]" doc:name="Set Payload"/>
<scripting:component doc:name="Groovy">
<scripting:script engine="Groovy"><![CDATA[def writer = new StringWriter()
def xml = new groovy.xml.MarkupBuilder(writer)
xml.mkp.xmlDeclaration(version: "1.0", encoding: "UTF-8")
xml.GetTicketByCode(xmlns: 'http://tempuri.org/') {
code(payload)
}
result = writer.toString() ]]></scripting:script>
</scripting:component>
<ws:consumer config-ref="Web_Service_Consumer" operation="GetTicketByCode" doc:name="Web Service Consumer"/>
</when>
<when expression="#[message.inboundProperties.'http.request.path' == "/validateTickets"]">
<scripting:component doc:name="Groovy">
<scripting:script engine="Groovy"><![CDATA[]]></scripting:script>
</scripting:component>
<ws:consumer config-ref="Web_Service_Consumer" operation="ValidateTicket" doc:name="Web Service Consumer"/>
</when>
</choice>
<mulexml:xslt-transformer xsl-file="removeattributes.xsl" maxIdleTransformers="2" maxActiveTransformers="5" doc:name="XSLT"/>
<json:xml-to-json-transformer doc:name="XML to JSON"/>
</flow>
INFO 2015-05-26 09:25:40,303 [[billeterie].HTTP_Listener_Configuration.worker.01] org.mule.module.http.internal.listener.HttpListenerRegistry: No listener found for request: (GET)/getTicketByTicketCode
INFO 2015-05-26 09:25:40,303 [[billeterie].HTTP_Listener_Configuration.worker.01] org.mule.module.http.internal.listener.HttpListenerRegistry: Available listeners are: [(*)/]
有没有办法使这项工作? 或唯一的方法是添加另一个类似于路径的queryParam。 谢谢
您可以使用以下path="/*"
并且我已将您的流程修改如下:-
<flow name="Tickets">
<http:listener config-ref="HTTP_Listener_Configuration" path="/*" doc:name="HTTP"/>
<logger message="#[message.inboundProperties.'http.listener.path']" level="INFO" doc:name="Logger"/>
<choice doc:name="Choice">
<when expression="#[message.inboundProperties.'http.request.path'.contains('/getTicketByTicketCode')]">
<logger message="getTicketByTicketCode flow" level="INFO" doc:name="Logger"/>
<set-payload value="#[message.inboundProperties.'http.query.params'.ticketcode]" doc:name="Set Payload"/>
<scripting:component doc:name="Groovy">
<scripting:script engine="Groovy"><![CDATA[def writer = new StringWriter()
def xml = new groovy.xml.MarkupBuilder(writer)
xml.mkp.xmlDeclaration(version: "1.0", encoding: "UTF-8")
xml.GetTicketByCode(xmlns: 'http://tempuri.org/') {
code(payload)
}
result = writer.toString() ]]></scripting:script>
</scripting:component>
<ws:consumer config-ref="Web_Service_Consumer" operation="GetTicketByCode" doc:name="Web Service Consumer"/>
</when>
<when expression="#[message.inboundProperties.'http.request.path'.contains('/validateTickets')]">
<logger message="validateTickets flow" level="INFO" doc:name="Logger"/>
<scripting:component doc:name="Groovy">
<scripting:script engine="Groovy"><![CDATA[]]></scripting:script>
</scripting:component>
<ws:consumer config-ref="Web_Service_Consumer" operation="ValidateTicket" doc:name="Web Service Consumer"/>
</when>
<otherwise>
<logger message="Other than this url " level="INFO" doc:name="Logger"/>
</otherwise>
<mulexml:xslt-transformer xsl-file="removeattributes.xsl" maxIdleTransformers="2" maxActiveTransformers="5" doc:name="XSLT"/>
<json:xml-to-json-transformer doc:name="XML to JSON"/>
</choice>
</flow>
现在,如果您的网址包含getTicketByTicketCode,则它将转到第一个流程,如果包含validateTickets,则它将转到第二个流程。...
否则,如果没有这两个中的任何一个,它将在其他情况下打印记录器
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.