[英]binding a service to multiple activities
我的服务已正确绑定到我的第一个活动,但是当我尝试将其绑定到第二个活动时,它不起作用这是onresume和我的第一个活动暂停时的代码
@Override
protected void onResume() {
super.onResume();
connection = new ServiceConnection() {
@Override
public void onServiceDisconnected(ComponentName name) {
service = null;
}
@Override
public void onServiceConnected(ComponentName name, IBinder service) {
shareInfos.this.service = (IService) service;
}
};
bindService(new Intent(this, shareInfos.class), connection,
Context.BIND_AUTO_CREATE);
}
@Override
protected void onPause() {
super.onPause();
if (service != null) {
service = null;
unbindService(connection);
}
}
我对第二个活动执行了相同的操作,但是当我尝试使用该服务时,它始终为null这是第二个活动的代码:
@Override
protected void onResume() {
super.onResume();
connection = new ServiceConnection() {
@Override
public void onServiceDisconnected(ComponentName name) {
service = null;
}
@Override
public void onServiceConnected(ComponentName name, IBinder service) {
shareInfos.this.service = (IService) service;
}
};
bindService(new Intent(this, shareInfos.class), connection,
Context.BIND_AUTO_CREATE);
}
@Override
protected void onPause() {
super.onPause();
if (service != null) {
service = null;
unbindService(connection);
}
}
那就是我服务的代码:
public class ExampleService extends AbstractService {
private static final String SERVICE_NAME = "ExampleService";
public ExampleService() {
super(SERVICE_NAME);
}
@Override
public AbstractRegistration getRegistration() {
return new AbstractRegistration() {
@Override
public String getApplicationName() {
return getResources().getString(R.string.application_name);
}
@Override
public String getApplicationDescription() {
return getResources().getString(R.string.application_description);
}
@Override
public PendingIntent getApplicationSettings() {
return PendingIntent.getActivity(getApplicationContext(), 0, new Intent(getApplicationContext(), ExampleActivity.class), 0);
}
@Override
public boolean requiresStorage() {
return true;
}
@Override
public boolean requiresQueries() {
return true;
}
@Override
public boolean requiresRecognition() {
return true;
}
};
}
}
这是我的清单文件:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="eu.gambas.example.android" >
<uses-sdk
android:minSdkVersion="10"
android:targetSdkVersion="15" />
<uses-permission android:name="eu.gambas.permission.ACCESS" />
<uses-permission
android:name="android.permission.WRITE_EXTERNAL_STORAGE"
android:maxSdkVersion="18" />
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
<uses-permission
android:name="android.permission.READ_EXTERNAL_STORAGE"
android:maxSdkVersion="18" />
<application
android:icon="@drawable/icon"
android:label="@string/application_name" >
<activity
android:name="com.example.egm.exampleandroid.ExampleActivity"
android:label="@string/application_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name="com.example.egm.exampleandroid.ResultActivity" />
<activity android:name="com.example.egm.exampleandroid.shareInfos" />
<activity android:name="com.example.egm.exampleandroid.testActivity" />
<service
android:name="com.example.egm.exampleandroid.ExampleService"
android:exported="true" >
<intent-filter>
<action android:name="eu.gambas.action.start" />
</intent-filter>
<intent-filter>
<action android:name="eu.gambas.action.stop" />
</intent-filter>
<intent-filter>
<action android:name="eu.gambas.action.result" />
</intent-filter>
</service>
</application>
在此先感谢您的帮助!
您必须在两个活动中使用Service调用的同一对象。 最好的方法是扩展Application类,在该类中您必须编写代码来启动服务和停止服务。然后,您可以从任何活动中访问服务。
public class AppController extends Application {
private static AppController mInstance;
private ExampleService service;
public static synchronized AppController getInstance() {
return mInstance;
}
@Override
public void onCreate() {
// TODO Auto-generated method stub
super.onCreate();
}
public void startService(){
//start your service
}
public void stopService(){
//stop service
}
public ExampleService getService(){
}
}
现在从活动中获取服务
AppController.getInstance().getService();
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