仅显示在下一条记录中具有相同值的第一列

Question

假设我有一张桌子

name ----------------------- phone ------------------------ address

Aldi ----------------------- 021345 ----------------------- Bogor

Aldi ------------------------021345 ----------------------- Jakarta

John ------------------------034566 ----------------------- Depok

如果在下一记录中具有相同的值，如何仅显示第一列？ 结果可能看起来像：

name ----------------------- phone ------------------------ address

Aldi ----------------------- 021345 ----------------------- Bogor

----------------------------------------------------------- Jakarta

John ----------------------- 034566 ----------------------- Depok

Answer 1

尝试这个

SQL小提琴演示

select t1.id,
case when t1.name = t2.name and t1.phone = t2.phone
then
'-'
else
t1.name
end as name,
case when t1.name = t2.name and t1.phone = t2.phone
then
'-'
else
t1.phone
end as phone,t1.address from test t1 left join test t2 on t2.id = t1.id-1
order by t1.id