[英]Database statement is not working in google chrome
我正在运行chrome 43.0
。 在控制台中,我正在以下命令下运行:
>> var db1 = openDatabase('testDB', '', 'my first database', 2 * 1024 * 1024, function(d){console.log(d);});
>> undefined
>> db1.transaction(function (tx) {
console.log(".....................");
console.log(tx.executeSql("INSERT INTO fileLog (fileName, bucketName) VALUES ('123','synergies')"));
});
>> undefined
.....................
undefined
问题是它没有在fileLog
表中插入任何数据。
您必须先创建表fileLog,然后将值插入到表中,如下所示:
db1.transaction(function (tx) {
tx.executeSql('CREATE TABLE IF NOT EXISTS fileLog (fileName,bucketName )'); });
您可以从中选择值
db1.transaction(function (tx) {
tx.executeSql('SELECT * FROM fileLog ', [], function (tx, results) {
for (var i = 0; i < results.rows.length; i++){
console.log(results.rows.item(i).fileName," ",results.rows.item(i).bucketName);
}
}, null);
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.