[英]mysqli display rows based on row value - (if row value=1 display, else hide)
[英]mysqli display data based on row ID value
我需要根据其他表中的值在一行中显示文本,我将解释...逐步变得非常清晰。
名为“链接”的表具有名为“ title_id”的行
来自“链接”的该行“ title_id”在名为“ id”的行的其他表中具有“相同”的值。
表“ titles”有另一行称为“ title”-tis是wath,我需要以这种方式显示...
a href = .... /> TABLE将行title_id =链接到表标题行ID->在此处显示表标题行标题(基于表链接中的行title_id)</ a ...
希望您能理解,结果必须是(a href = ...> TEXT MOVIE TITLE </ a>)
这是我需要更改的基本代码(我已经注释了需要更改的部分):
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "dbname";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, label, title_id, season, episode, approved FROM links WHERE approved = 1 order by id desc LIMIT 30 OFFSET 1";
$result = $last_id = $conn->query($sql);
if ($result->num_rows > 0)
{
echo "<table><tr><th>ID</th><th>Audio</th><th>URL</th><th>Temporada</th><th>Episodio</th><th>Aprobado</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["id"]."</td><td>".$row["label"]."</td>";
echo "<td>";
if (empty($row['episode'])) {
echo "<a href=";
echo '/peliculas-online/'.$row["title_id"];
echo ">HERE MUST HAVE THE VALUE FROM TABLE titles -> row title - based on $row["title_id"] </a>";
// -------------------------
}
else {
echo "<a href=";
echo '/series-online/'.$row['title_id'].'/seasons/'.$row['season'].'/episodes/'.$row["episode"];
echo ">HERE MUST HAVE THE VALUE FROM TABLE titles -> row title - based on $row["title_id"] </a>";
// -----------------------------------
}
echo "</td>";
echo "<td>".$row["season"]."</td><td>".$row["episode"]."</td><td>".$row["approved"]."</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
您只需要稍微修改一下查询即可获取此信息。 您可以像这样在这些ID上加入标题:
SELECT l.id, l.label, l.title_id, t.title, l.season, l.episode, l.approved
FROM links l
JOIN titles t
ON l.title_id = t.id
WHERE approved = 1
ORDER by id DESC
LIMIT 30 OFFSET 1
然后,您可以像以前一样调用变量。 同一查询将具有row['title']
了解有关MySQL联接的更多信息
要在脚本中获取此信息,只需替换以下行:
echo ">HERE MUST HAVE THE VALUE FROM TABLE titles -> row title - based on $row["title_id"] </a>";
有了这个:
echo '>'.$row['title'].'</a>';
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