正则表达式的日期，并使用stringByReplacingMatchesInString替换其在字符串中的出现

Question

我需要一个这样的日期正则表达式，“ dd / mm / yyyy hh：mm：ss pm”，然后我想在某些NSString使用此正则表达式匹配项来分隔字符串组件。

例如，如果字符串是，

30/06/15 11:46:37 pm: Person1: Testing
30/06/15 11:46:40 pm: Person1: Hello...
30/06/15 11:46:52 pm: Person2: Hi 
30/06/15 11:47:06 pm: Person1: How are you doing

数组中的输出组件应该是

Person1: Testing
Person1: Hello...
Person2: Hi 
Person1: How are you doing

您可以提出任何更好的主意来解析包含上述聊天文本的字符串。

Answer 1

Try This,
NSString *string = @"30/06/15 11:46:37 pm: Person1: Testing 30/06/15 11:46:40 pm: Person1: Hello... 30/06/15 11:46:52 pm: Person2: Hi 30/06/15 11:47:06 pm: Person1: How are you doing";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"([0-9]{1,2})+\/+([0-9]{1,2})+\/+([0-9]{1,2})+ +([0-9]{1,2})+:+([0-9]{1,2})+:+([0-9]{1,2}) +(am|pm): " options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];
NSLog(@"%@", modifiedString);