如何在JavaScript中重新格式化数据

Question

如果我的问题不清楚，我事先道歉，我才刚刚开始学习Javascript，这是我的第一篇文章。我正在尝试重新格式化数据集：

console.log(dataset)显示以下内容（我在这里显示一些记录）：

[{"name":"HPH","income":["1976","2434"]},
{"name":"HPH","income":["1977","1658"]},
{"name":"HPH","income":["1978","1712"]},
{"name":"SWO","income":["1976","9913"]},
{"name":"SWO","income":["1977","8852"]},
{"name":"SWO","income":["1978","7152"]}]

我想得到以下内容：

[{"name":"HPH","income":[["1976","2434"],["1977","1658"],["1978","1712"]]},
{"name":"SWO","income":[["1976","9913"],["1977","8852"],["1978","7152"]]}]

任何帮助都感激不尽。

坦率

Answer 1

尝试这样的事情：

var data = [{"name":"HPH","income":["1976","2434"]},
{"name":"HPH","income":["1977","1658"]},
{"name":"HPH","income":["1978","1712"]},
{"name":"SWO","income":["1976","9913"]},
{"name":"SWO","income":["1977","8852"]},
{"name":"SWO","income":["1978","7152"]}];

var final = [],
    found = false,
    i, j;
for (i in data) {
    for(j in final) {
        if (final[j].name == data[i].name) {
            found = true;
            final[j].income.push(data[i].income);
            break;
        }
    }

    if (found) {
        found = false;
        continue;
    }

    var obj = {name: data[i].name, income: [data[i].income]};
    final.push(obj);
}

console.log(final);

http://jsfiddle.net/wqq1t2zj/

Answer 2

var a = [{"name":"HPH","income":["1976","2434"]},
{"name":"HPH","income":["1977","1658"]},
{"name":"HPH","income":["1978","1712"]},
{"name":"SWO","income":["1976","9913"]},
{"name":"SWO","income":["1977","8852"]},
{"name":"SWO","income":["1978","7152"]}],
    b = {},
    c = [];
for(var i = 0; i < a.length; i++) {
    if(!b[a[i].name])b[a[i].name] = [];
    for(var j = 0; j < a[i].income.length){
        b[a[i].name].push(a[i].income[j]);
    }
}

// Here you have an object like 
// b = {HPH : ["1976","2434", "1978","1712"], SWO : ["1977","8852", "1977","8852","1978","7152"};
for(var k in b){
    c.push({name : k, income : b[k]}
}

我邀请您阅读：很有口才的JS ，如果您有成为专家的动机（ MDN （ Arrays ）），那么这是非常有用的阅读！

Answer 3

也可以尝试，仅使用filter和reduce ：

 var dataset = [{"name":"HPH","income":["1976","2434"]},{"name":"HPH","income":["1977","1658"]},{"name":"HPH","income":["1978","1712"]},{"name":"SWO","income":["1976","9913"]},{"name":"SWO","income":["1977","8852"]},{"name":"SWO","income":["1978","7152"]}]; var result = dataset.reduce(function(data, item){ var existitem = data.filter(function(i){ return i.name === item.name })[0] || {name: item.name, income: []}; !existitem.income.length && data.push(existitem); existitem.income.push(item.income); return data }, []) document.write(JSON.stringify(result))