仅返回符合条件的记录的id

Question

我需要返回满足以下条件的记录的不同ID：必须具有字段reason_of_creation = 1的记录，并且必须不具有字段reason_of_creation = 0或同时为null的记录。 虽然我能够做到这一点，但我一直在想是否有更优雅（甚至推荐）的方式。

这是我拥有的匿名版本：

select distinct st.some_id from (
        select st.some_id, wanted.wanted_count as wanted, unwanted.unwanted_count as unwanted
          from some_table st
          left join (
                select st.some_id, count(st.reason_of_creation) as wanted_count
                  from some_table st
                 where st.reason_of_creation=1
                 group by st.some_id
                 ) wanted on wanted.some_id = st.some_id
          left join (
                select st.some_id, count(st.reason_of_creation) as unwanted_count
                  from some_table st
                 where st.reason_of_creation=0
                 group by st.some_id
                 ) unwanted on unwanted.some_id = st.some_id
where wanted.wanted_count >0 and (unwanted.unwanted_count = 0 or unwanted.unwanted_count is null)
   ) st;

样本数据 ：

some_id    reason_of_creation
      1           1
      1           0
      2           1
      3           null
      4           0
      4           1
      5           1

期望的结果将是some_id = 2, 5的记录列表

Answer 1

在我看来你的查询是矫枉过正，你需要的只是一些后期聚合过滤

SELECT some_id FROM t
GROUP BY some_id
HAVING SUM(CASE WHEN reason_of_creation = 1 THEN 1 ELSE 0 END)>0
AND SUM(CASE WHEN reason_of_creation = 0 OR reason_of_creation IS NULL THEN 1 ELSE 0 END)=0

Answer 2

我认为存在更优雅的查询，它基于假设reasoson_of_crdeation字段是整数，所以最小可能它的值，大于0是1

这是针对reasoson_of_crdeation可能的负值：

select someid from st
where reasoson_of_crdeation != -1
group by someid
having(min(nvl(abs(reasoson_of_crdeation), 0)) = 1)

要么

select someid from st
group by someid
having(min(nvl(abs(case when reasoson_of_crdeation = -1 then -2 else reasoson_of_crdeation end), 0)) = 1)

如果reasoson_of_crdeation是非负整数，则在这种情况下：

select someid from st
group by someid
having(min(nvl(reasoson_of_crdeation, 0)) = 1)