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[英]How can I deserialize an object from an XML returned from a nusoap service?
[英]deserialize an XML object returned from SQL query?
我需要反序列化一个“应该”从SQL查询返回的XML对象。
我有这个在JSON中工作,但不能使用JSON所以我转移到XML。 JsonConvert功能将我的结果放在一行..但我不确定如何处理SQL给我的结果。
当写入服务器时,Table将获取Xdocument类型到xml数据类型单元格中。
if (do_sql_read)
{
List<string> usernames = new List<string>();
List<int> ids = new List<int>();
string sql_load;
Player player_after_load = new Player();
//multiple
string select_string = @"SELECT * FROM [Table]";
using (SqlConnection sql_connection_a = new SqlConnection( GetConnectionString() ) )
{
sql_connection_a.Open();
using (SqlCommand command = new SqlCommand(select_string, sql_connection_a))
{
SqlDataReader reader = command.ExecuteReader(CommandBehavior.Default);
// XML VERSION
while (reader.Read())
{
int iii = reader.GetInt32(0); // unique id int
string name = reader.GetString(1); // Name string
sql_load = reader.GetString(2);
usernames.Add(name);
ids.Add(iii);
XmlSerializer XML_serializer = new XmlSerializer (typeof(Player));
// <<<<< THIS PART ??? >>>
player_after_load = (Player)XML_serializer.Deserialize (sql_load);
Console.WriteLine("SQLPlayer: " + iii + " " + player_after_load.name + " " + player_after_load.health + " " + player_after_load.mana);
}
/* JSON VERSION WORKS
while (reader.Read())
{
int iii = reader.GetInt32(0); // unique id int
string name = reader.GetString(1); // Name string
sql_load = reader.GetString(2);
usernames.Add(name);
ids.Add(iii);
player_after_load = JsonConvert.DeserializeObject<Player>(sql_load);
Console.WriteLine("SQLPlayer: " + iii + " " + player_after_load.name + " " + player_after_load.health + " " + player_after_load.mana);
}
*/
}
}
} // end do_sql_string
XMLSerializer的Deserialize
方法没有任何带字符串的重载。 您可以使用Stream
(使用MemoryStream )代替:
using (var ms = new MemoryStream(Encoding.UTF8.GetBytes(xml))) {
player_after_load = (Player)XML_serializer.Deserialize(ms);
}
Ps:你的变量名很糟糕。 您应该看到C#编码约定。
我只是添加了这个答案,因为你说你不能使用System.IO。 如果您可以使用System.IO,请参阅DatVM的答案。 以下是您可以执行的操作示例。 我简化了这一点,它包含一个反序列化的类,它可以在任何控制台应用程序中运行。
using System;
using System.Xml;
using System.Xml.Serialization;
public class Player
{
public string Name {get; set;}
}
public class Program
{
public static void Main()
{
var str = "<Player><Name>Bobby</Name></Player>";
var doc = new XmlDocument();
var XML_serializer = new XmlSerializer(typeof(Player));
doc.LoadXml(str);
Player player_after_load;
using (var nodeReader = new XmlNodeReader(doc))
{
player_after_load = (Player)XML_serializer.Deserialize(nodeReader);
}
Console.WriteLine(player_after_load.Name);
}
}
控制台结果
Bobby
但在此之前,您需要使用[Serializable]
属性创建类:
[Serializable]
public class MyObject
{
public int n1;
public int n2;
public String str;
}
然后使用标准反序列化器:
IFormatter formatter = new BinaryFormatter();
MyObject obj = (MyObject) formatter.Deserialize(your_xml_object);
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