如何在PHP中迭代JSON

Question

在以下JSON中，我想获取所有客户电话并存储在数组中：

{  
   "MetaInformation":{  
      "@TotalResources":1,
      "@TotalPages":1,
      "@CurrentPage":1
   },
   "Customers":[  
      {  
         "@url":"https:\/\/URL/customers\/1",
         "Address1":"Mumbai",
         "City":"Mumbai",
         "CustomerNumber":"1",
         "Email":"xyz@gmail.com",
         "Name":"Saurabh Pradhan",
         "OrganisationNumber":"",
         "Phone":"91xxx",
         "ZipCode":"45153"
      }
   ]
}

我尝试使用以下方法，但始终使我抛出错误“尝试获取非对象的属性”：

$customer_json = json_decode($api->getAllCustomers());    
$customer_json->Customers[0]->Phone;

Answer 1

问题在于，JSON对象的PHP表示形式不是对象。 PHP使用关联数组代替。 为方便起见，请使用：

$customer_json = json_decode($api->getAllCustomers(), true);
$customer_json['Customers'][0]['Phone'];