[英]Convert a ruby nested hash in array of hashes
我正在尝试整理嵌套的哈希。 我的哈希具有以下结构:
{
"errorDescription":"",
"message":"",
"resultCode":"OK",
"resultObj":{
"categoryList":[
{
"asNew":"N",
"categoryId":40000000,
"categoryList":[
{
"asNew":"N",
"categoryId":40000007,
"categoryList":[
],
"categoryName":"CATALOGO",
"categoryType":"TYPE_NODE",
"contentId":40000007,
"contentTitle":"CATALOGO",
"contentType":"CATEGORY_NODE",
"orderId":0,
"urlPictures":""
},
{
"asNew":"N",
"categoryId":40000018,
"categoryList":[
{
"asNew":"N",
"categoryId":40000019,
"categoryList":[
],
"categoryName":"CANALI CALCIO",
"categoryType":"TYPE_VOD",
"contentId":40000019,
"contentTitle":"CALCIO & SPORT",
"contentType":"CATEGORY_LEAF",
"orderId":0,
"urlPictures":""
},
{
"asNew":"N",
"categoryId":40000020,
"categoryList":[
],
"categoryName":"CANALI CINEMA",
"categoryType":"TYPE_VOD",
"contentId":40000020,
"contentTitle":"CINEMA & SERIE",
"contentType":"CATEGORY_LEAF",
"orderId":1,
"urlPictures":""
}
],
"categoryName":"CANALI TV",
"categoryType":"TYPE_NODE",
"contentId":40000018,
"contentTitle":"CANALI TV",
"contentType":"CATEGORY_NODE",
"orderId":1,
"urlPictures":""
}
],
"categoryName":"ROOT",
"categoryType":"TYPE_NODE",
"contentId":40000000,
"contentTitle":"ROOT",
"contentType":"",
"orderId":0,
"urlPictures":""
}
]
}
}
我必须将此哈希转换为对象数组,其中每个对象都具有以下结构:
{
"asNew":"N",
"categoryId":40000007,
"categoryName":"CATALOGO",
"categoryType":"TYPE_NODE",
"contentId":40000007,
"contentTitle":"CATALOGO",
"contentType":"CATEGORY_NODE",
"orderId":0,
"urlPictures":""
}
基本上,每个键“ categoryList”都有一个数组作为值,并且此数组具有一个或多个散列,以及另一个键“ categoryList”。 我必须将每个categoryList数组中的所有对象移动到没有categoryList'key'的另一个数组中。
编辑
我将此方法添加到哈希类
class Hash
def find_all_values_for(key)
result = []
result << self[key]
unless self.values.nil?
self.values.each do |values|
values = [values] unless values.is_a? Array
values.each do |value|
result += value.find_all_values_for(key) if value.is_a? Hash
end
end
end
result.flatten.compact
end
end
我映射删除了CategoryList键的结果数组
h.map { |c| c.except!('categoryList') }
它可以工作,但是有一种更有效的方法。
此代码将返回请求的对象数组。
def flatten_categoryList(categoryList)
categoryList.inject([]) do |result, item|
result + flatten_categoryList(item.delete("categoryList")) << item
end
end
flatten_categoryList(h["resultObj"]["categoryList"])
我无法运行您的软件来获得基准,因此判断解决方案目前是主观的。
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