自定义列表视图中的OnItemClickListener

Question

我有一个带有搜索的列表视图，该列表可以正常工作，只是根据依赖于列表视图数组位置的第二个数组显示正确的详细信息。 如果我不搜索列表，则单击项目后所有内容均显示完美，但是如果我搜索然后单击该项目，它将返回项目位置而不是数组位置，我将如何获得项目数组位置。 我的职位必须基于数字。 像0,1,2,3，...谢谢。 任何帮助请。 你是我最后的希望

public class Main extends Activity {
EditText edittext;
ListView listview;

String[] text;

int textlength = 0;
ArrayList<String> text_sort = new ArrayList<String>();

public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    text = new String[23];
    for (int x = 1; x < 23 + 1; x = x + 1) {
        String this_subject = "subject_" + String.valueOf(x);
        int resID = getResources().getIdentifier(this_subject, "string",
                getPackageName());
        text[x - 1] = getResources().getString(resID);
    }

    edittext = (EditText) findViewById(R.id.EditText01);
    listview = (ListView) findViewById(R.id.ListView01);
    listview.setAdapter(new MyCustomAdapter(text, null));
    edittext.addTextChangedListener(new TextWatcher() {

        public void afterTextChanged(Editable s) {

        }

        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {

        }

        public void onTextChanged(CharSequence s, int start, int before,
                int count) {

            textlength = edittext.getText().length();
            text_sort.clear();

            for (int i = 0; i < text.length; i++) {
                if (textlength <= text[i].length()) {
                    if (edittext
                            .getText()
                            .toString()
                            .equalsIgnoreCase(
                                    (String) text[i].subSequence(0,
                                            textlength))) {
                        text_sort.add(text[i]);

                    }
                }
            }

            listview.setAdapter(new MyCustomAdapter(text_sort, null));

        }
    });
    listview.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                int position, long id) {
            // Here I have to send the location of each item to an intent

            //this code send it without search action

            /*Intent i = new Intent(getApplicationContext(), myclass);
            String Subject_number = String.valueOf(position + 1);
            i.putExtra("subject_number", Subject_number);
            startActivity(i);*/

        }
    });
}

class MyCustomAdapter extends BaseAdapter {

    String[] data_text;

    MyCustomAdapter() {

    }

    MyCustomAdapter(String[] text, int[] image) {
        data_text = text;

    }

    MyCustomAdapter(ArrayList<String> text, ArrayList<Integer> image) {
        data_text = new String[text.size()];

        for (int i = 0; i < text.size(); i++) {
            data_text[i] = text.get(i);

        }

    }

    public int getCount() {
        return data_text.length;
    }

    public String getItem(int position) {
        return null;
    }

    public long getItemId(int position) {
        return position;
    }

    public View getView(int position, View convertView, ViewGroup parent) {

        LayoutInflater inflater = getLayoutInflater();
        View row;

        row = inflater.inflate(R.layout.listview, parent, false);

        TextView textview = (TextView) row.findViewById(R.id.TextView01);

        textview.setText(data_text[position]);
        Animation animation = AnimationUtils.loadAnimation(
                getApplicationContext(), R.anim.slide_in_right);
        row.startAnimation(animation);
        return (row);

    }

}

Answer 1

确保您在listview的项目布局中不要声明button或imagebutton，因为这会使onitemclicklistener不起作用

Answer 2

我想我已经找到了解决方案。 使用以下代码。

listview.setOnItemClickListener(new OnItemClickListener() {

    @Override
    public void onItemClick(AdapterView<?> parent, View view,
            int position, long id) {
        int orgPos;
        if (text.length != text_sort.size() ) {
            // The list on which we clicked is sorted!
            String clickedText = text_sort.get(position);
            int i = 0; boolean found = false;

            while  ( i < text.length && found == false) {
                if (clickedText == text[i]) {
                    orgPos = i;
                    found = true;
                }
                else { i++; }
            }
        }
        else { 
            // Original List click happened
            orgPos = position;
        }
        // You got original position as orgPos now intent
    }
});

我没有测试代码，但是随时使用类似的方法。 让我知道它是否可以解决您的问题。

Answer 3

谢谢大家。

此代码有效：

            @Override
        public void onItemClick(AdapterView<?> parent, View view,
                int position, long id) {
            int orgPos = 0;
            if (text.length != text_sort.size()) {
                // The list on which we clicked is sorted!
                String clickedText = text_sort.get(position);
                int i1 = 0;
                boolean found = false;

                while (i1 < text.length && found == false) {
                    if (clickedText == text[i1]) {
                        orgPos = i1;
                        found = true;
                    } else {
                        i1++;
                    }
                }
                Intent i2 = new Intent(getApplicationContext(),
                        Secendbardari1.class);
                String Subject_number = String.valueOf(orgPos + 1);
                i2.putExtra("subject_number", Subject_number);
                startActivity(i2);

            } else {
                Intent i = new Intent(getApplicationContext(),
                        Secendbardari1.class);
                String Subject_number = String.valueOf(position + 1);
                i.putExtra("subject_number", Subject_number);
                startActivity(i);

            }

        }