[英]C# XML Document Error (2,2) deserialize xml and storing to array
目的:-反序列化xml文档中的数据并将其存储为数组。 -避免手动将数据分配给不同的字符串。 -xml文档将手动生成
public void DeserializeObject(string filename)
{
try
{
XmlSerializer deserializer = new XmlSerializer(typeof(string[]));
FileStream fs = new FileStream(filename, FileMode.Open);
string[] XmlData = (string[])deserializer.Deserialize(fs);
foreach (string p in XmlData)
{
Console.WriteLine(p);
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
}
XML文件如下
<?xml version="1.0" encoding="utf-8"?>
<Mapping xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Products>
<Product>
<software>Seiko</software>
</Product>
<Product>
<hardware>Martina</hardware>
</Product>
</Products>
</Mapping>
尝试这个
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication38
{
class Program
{
static void Main(string[] args)
{
string input =
"<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
"<Mapping xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">" +
"<Products>" +
"<Product>" +
"<software>Seiko</software>" +
"</Product>" +
"<Product>" +
"<hardware>Martina</hardware>" +
"</Product>" +
"</Products>" +
"</Mapping>";
XDocument doc = XDocument.Parse(input);
var results = doc.Descendants("Product").Select(x =>
x.Elements().Select(y => new { type = y.Name, value = (string)y }).ToList()
).SelectMany(z => z).ToList();
var groups = results.GroupBy(x => x.type).ToList();
}
}
}
谢谢,找到了这个解决方案
<?xml version="1.0" encoding="utf-8" ?>
<Locations>
<Location Name="Location1" IP="127.0.0.1"></Location>
<Location Name="Location2" IP="127.0.0.1"></Location>
<Location Name="Location3" IP="127.0.0.1"></Location>
<Location Name="Location4" IP="127.0.0.1"></Location>
<Location Name="Location5" IP="127.0.0.1"></Location>
</Locations>
using System.Xml.Linq;
class Program
{
static void Main(string[] args)
{
string[] strarr = GetStringArray("Locations.xml");
foreach (string str in strarr)
{
Console.WriteLine(str);
}
}
public static string[] GetStringArray(string url)
{
XDocument doc = XDocument.Load(url);
var locations = from l in doc.Descendants("Location")
select (string)l.Attribute("Name");
return locations.ToArray();
}
}
您需要从示例XML生成一个类。 您可以使用xsd.exe生成.xsd,然后从中创建.cs文件。
您需要将此类型添加到XmlSerializer
看到这个答案: 从XML生成C#类
XmlSerializer deserializer = new XmlSerializer(typeof(Mapping)); <- Created class type here.
如果您要做的只是从XML文档中获取数据作为字符串数组,则可以使用XmlDocument加载数据
XmlDocument doc = new XmlDocument();
doc.Load("file.xml");
然后,您可以使用xPath表达式找到所需的节点:
XmlNodeList nodelist = doc.SelectNodes(...);
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