[英]C++ - overloading operator >> for my string class
我意识到字符串类MyString。 这是代码:
#include <iostream>
#include <cstring>
using std::cout;
using std::endl;
class MyString{
private:
char * content;
int length;
void copy(const MyString & source);
public:
MyString();
MyString(const char * source);
~MyString();
MyString(const MyString & source);
void print(void);
MyString & operator = (const MyString &source);
friend std::ostream & operator << (std::ostream & out, const MyString& towrite);
friend std::istream & operator >> (std::istream & in, MyString & toread);
};
MyString::MyString(){
content = new char[1];
content[0] = '\0';
length = 0;
}
MyString::MyString(const char *source){
length = strlen(source);
content = new char[length + 1];
strcpy(content, source);
}
MyString::~MyString(){
delete[] content;
}
void MyString::copy(const MyString & source){
length = source.length;
content = new char[length + 1];
strcpy(content, source.content);
}
MyString::MyString(const MyString & source){
copy(source);
}
void MyString::print(void){
cout << "" << content << endl;
}
MyString &MyString::operator=(const MyString &source){
copy(source);
return *this;
}
std::ostream & operator<<(std::ostream & out,const MyString& towrite){
out << towrite.content;
return out;
}
std::istream & operator >> (std::istream & in, MyString & toread){
int length;
std::cout << "Enter length of word: " << endl;
std::cin >> length;
toread.length = length;
toread.content = new char[toread.length+1];
for (int i = 0; i < toread.length; i++){
in >> toread.content[i] ;
}
toread.content[toread.length] = '\0';
return in;
}
我的问题与重载运算符>>有关。
对于此主程序:
int main(){
MyString word;
std::cout<<"Enter some word: "<<endl;
std::cin>>word;
std::cout<<"Your entered: "<<word<<endl;
}
这是输出:
Enter some word:
Enter length of word:
5
stack
Your entered: stack
Process returned 0 (0x0) execution time : 8.313 s
Press any key to continue.
它可以正确打印用户输入的字符串,但不会按照我想要的方式“模仿”原始字符串类。 这就是为什么。
如果使用C ++字符串类:
int main(){
std::string word;
std::cout<<"Enter some word: "<<endl;
std::cin>>word;
std::cout<<"Your entered: "<<word<<endl;
}
用户无需输入单词长度 。 我可以在课堂上实现吗?
EDIT1:
我这样做是这样的:
std::istream & operator >> (std::istream & in, MyString & toread){
char *temp;
temp = new char[100];
char c;
int i = 0;
while(c != '\n'){
c = getchar();
temp[i++] = c;
}
temp[i] = '\0';
int length = i-1;
toread.length = length;
toread.content = new char[toread.length+1];
for(int i = 0 ; i < toread.length ; i++){
toread.content[i] = temp[i];
}
delete [] temp;
toread.content[toread.length+1]='\0';
}
它可以正常工作。 但是,我得到警告,因为我没有返回“ in”:
|| ===构建:在fdsfsdf中调试(编译器:GNU GCC编译器)=== | C:\\ Users \\ hae \\ Desktop \\ fdsfsdf \\ main.cpp ||在函数'std :: istream&operator >>(std :: istream&,MyString&)':| C:\\ Users \\ hae \\ Desktop \\ fdsfsdf \\ main.cpp | 137 |警告:函数中没有返回非空[-Wreturn-type] |的return语句 || ===构建完成:0个错误,1个警告(0分钟,4秒)=== | || ===运行:在fdsfsdf中调试(编译器:GNU GCC编译器)=== |
这是我很久以前写的类似课程的精简版。 这是古董,但它可以工作,并解决班上的一些问题。
class charray {
public:
charray();
~charray();
charray(const charray&);
charray(const char*);
charray& operator=(const charray&);
charray& operator=(const char*);
void swap(charray&);
const char* c_str() const
{ return m_elem; }
unsigned int size() const
{ return m_size; }
private:
void m_resize(unsigned int size);
char* m_elem;
unsigned int m_size;
};
// private.
void charray::m_resize(unsigned int size)
{
char* elem = new char[size+1];
memcpy(elem, m_elem, std::min(m_size, size));
elem[size] = '\0';
delete [] m_elem;
m_elem = elem;
m_size = size;
}
// public.
charray::charray()
: m_elem(0), m_size(0)
{
m_resize(0);
}
charray::~charray()
{
delete [] m_elem;
}
charray::charray(const charray& src)
: m_elem(0), m_size(0)
{
unsigned int size = src.size();
m_resize(size);
memcpy(m_elem, src.c_str(), size);
}
charray::charray(const char* src)
: m_elem(0), m_size(0)
{
unsigned int size = std::strlen(src);
m_resize(size);
memcpy(m_elem, src, size);
}
charray& charray::operator=(const charray& rhs)
{
charray temp(rhs);
this->swap(temp);
return *this;
}
charray& charray::operator=(const char* rhs)
{
charray temp(rhs);
this->swap(temp);
return *this;
}
void charray::swap(charray& b)
{
std::swap(m_elem, b.m_elem);
std::swap(m_size, b.m_size);
}
这是您可能最感兴趣的。请密切注意细节。 当直接处理内存时,有效的实现与崩溃的实现之间的区别通常非常微妙。
注意:操作员不是朋友。 他们不访问私人数据。
std::ostream& operator<<(std::ostream& out, const charray& in)
{
return out << in.c_str();
}
std::istream& operator>>(std::istream& in, charray& out)
{
// verify no errors are set, flush tied streams, strip leading
// whitespace.
std::istream::sentry sentry(in);
if (!sentry)
return in;
unsigned int size = 0;
unsigned int tail = 0;
char* temp = 0;
int next; // @note int not char (to record EOF).
while ((next = in.get()) != in.eof() && !std::isspace(next)) {
// if temp buffer is exhausted, then double the buffer size.
// (base size of 16).
if (tail == size) {
unsigned int newsize = std::max(2*size, 16u);
char* newtemp = new char[newsize+1];
memcpy(newtemp, temp, size);
delete [] temp;
temp = newtemp;
size = newsize;
}
temp[tail++] = next;
}
// @note because the stream is prepeared with istream::sentry, there
// will be at least one non-whitespace character in the stream.
assert(temp != 0);
temp[tail] = '\0';
out = temp;
delete [] temp;
return in;
}
一种更简单,更安全的方法来进行完全相同的操作,
#include <vector>
std::istream& operator>>(std::istream& in, charray& out)
{
std::istream::sentry sentry(in);
if (!sentry)
return in;
std::vector<char> temp;
int next;
while ((next = in.get()) != in.eof() && !std::isspace(next))
temp.push_back(next);
temp.push_back('\0');
out = &temp[0];
return in;
}
编辑
以上内容已过时(C ++ 11之前的版本)。 现代的实现可能会以不同的方式处理构造和分配。 这是这些方法的更新版本,
注意:方法m_resize
消失了。 一切都通过构造函数来处理。
charray::charray(const char* src, unsigned int size)
: m_elem{ new char[size+1]{} }, m_size{ size }
{
std::copy(src, src + size, m_elem);
}
charray::charray()
: charray(nullptr, 0)
{}
charray::charray(const charray& src)
: charray(src.m_elem, src.m_size)
{}
charray::charray(const char* src)
: charray(src, std::strlen(src))
{}
charray::charray(charray&& src)
: m_elem{ src.m_elem }, m_size{ src.m_size }
{
src.m_elem = nullptr;
src.m_size = 0;
}
// handle both move and copy assignment.
charray& charray::operator=(charray rhs)
{
this->swap(rhs);
return *this;
}
希望这可以帮助。 祝好运。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.