PHP Regex在同一行上分别匹配模式

Question

我正在尝试使用php regex解析文本。 我写了一个符合所有条件的模式匹配。 我不想要这个。 它必须在同一行上分别匹配目标。

模式：

/\((?P<type>\w+)((,)*(?P<params>[\d\w\:]+))((,)*(?P<comment>.*))\)/u

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目标数据字符串：

lorem ipsum dolor (photo,61) test (photo,62,some text) (video,63) sit amet etc

---

结果为preg_match_all和PREG_SET_ORDER标志：

array (size=1)
0 => 
    array (size=11)
      0 => string '(photo,61) test (photo,62,some text) (video,63)' (length=47)
      'type' => string 'photo' (length=5)
      1 => string 'photo' (length=5)
      2 => string ',61' (length=3)
      3 => string ',' (length=1)
      'params' => string '61' (length=2)
      4 => string '61' (length=2)
      5 => string ') test (photo,62,some text) (video,63' (length=37)
      6 => string '' (length=0)
      'comment' => string ') test (photo,62,some text) (video,63' (length=37)
      7 => string ') test (photo,62,some text) (video,63' (length=37)

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如果目标数据放在单独的行中，并且执行相同的正则表达式模式，则结果为； （我想要这些结果，但没有换行）

lorem ipsum dolor 
(photo,61) test 
(photo,62,some text) 
(video,63) sit amet etc

array (size=3)
    0 => 
        array (size=11)
          0 => string '(photo,61)' (length=10)
          'type' => string 'photo' (length=5)
          1 => string 'photo' (length=5)
          2 => string ',61' (length=3)
          3 => string ',' (length=1)
          'params' => string '61' (length=2)
          4 => string '61' (length=2)
          5 => string '' (length=0)
          6 => string '' (length=0)
          'comment' => string '' (length=0)
          7 => string '' (length=0)
      1 => 
        array (size=11)
          0 => string '(photo,62,some text)' (length=20)
          'type' => string 'photo' (length=5)
          1 => string 'photo' (length=5)
          2 => string ',62' (length=3)
          3 => string ',' (length=1)
          'params' => string '62' (length=2)
          4 => string '62' (length=2)
          5 => string ',some text' (length=10)
          6 => string ',' (length=1)
          'comment' => string 'some text' (length=9)
          7 => string 'some text' (length=9)
      2 => 
        array (size=11)
          0 => string '(video,63)' (length=10)
          'type' => string 'video' (length=5)
          1 => string 'video' (length=5)
          2 => string ',63' (length=3)
          3 => string ',' (length=1)
          'params' => string '63' (length=2)
          4 => string '63' (length=2)
          5 => string '' (length=0)
          6 => string '' (length=0)
          'comment' => string '' (length=0)
          7 => string '' (length=0)

谢谢你的帮助。

Answer 1

只需使用代替

'~\(.*?\)~'

它会完成的

Regex101 评估

Answer 2

我发现一个解决方案不影响换行符（根本解决方案是在不使用“ /.../”的情况下以“〜...〜”括起来）

~\((\w+),([\d|:]+),*(.*?)\)~u

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命名版本；

~\((?P<type>\w+),(?P<params>[\d|:]+),*(?P<comment>.*?)\)~u

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感谢@Uchiha前置解决方案，也感谢您提供的提示。

'~\(.*?\)~'