如何编写用于json反序列化的initbinder？

Question

我有以下POJO：

class MyClass{
    ...
    HttpStatus httpStatus = HttpStatus.OK //from org.springframework.http
    @JsonIgnore
    public HttpStatus getHttpStatus() {
        return httpStatus;
     }

    @JsonProperty(value = "HttpStatus")
    public void setHttpStatus(HttpStatus httpStatus) {
        this.httpStatus = httpStatus;
    }
    ....
}

当我从表单接受（construct）对象以将String正确转换为InitBinder我已经写了InitBinder ：

@InitBinder
public void initBinder(WebDataBinder binder) {
    binder.registerCustomEditor(HttpStatus.class, new PropertyEditorSupport() {
        public void setAsText(String code) {
            if (StringUtils.isNotBlank(code)) {
                setValue(HttpStatus.valueOf(Integer.parseInt(code)));
            }
        }
    });

对于形式，它很酷。

我也有接受json的控制器方法：

@RequestMapping(value = "sendData.json", method = RequestMethod.POST, consumes = "application/json;charset=UTF-8",
            headers = "content-type=application/x-www-form-urlencoded")
    @ResponseStatus(HttpStatus.NO_CONTENT)
    public void putJsonData(@RequestBody MyClass myClass) {
        ....
    }

我这样传递httpStatus：

...
"HttpStatus":500
...

但是它转换不正确，我看到以下错误消息：

Bad Request","exception":"org.springframework.http.converter.HttpMessageNotReadableException","message":"Could not read JSON: Can not construct instance of org.springframework.http.HttpStatus from number value (500): index value outside legal index range [0..65]\n

据我了解，它转换不正确。

如何自定义此过程？

Answer 1

这样解决了问题：

class MyClass{
    ...
    HttpStatus httpStatus = HttpStatus.OK //from org.springframework.http
    @JsonIgnore
    public HttpStatus getHttpStatus() {
        return httpStatus;
     }

    @JsonProperty(value = "HttpStatus")
    @JsonDeserialize(using = HttpStatusDeserializer.class)
    public void setHttpStatus(HttpStatus httpStatus) {
        this.httpStatus = httpStatus;
    }
    ....
}

和反序列化器：

public class HttpStatusDeserializer extends JsonDeserializer<HttpStatus> {    
    @Override
    public HttpStatus deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
        ObjectCodec oc = jsonParser.getCodec();
        JsonNode node = oc.readTree(jsonParser);
        return HttpStatus.valueOf(Integer.parseInt(node.asText()));
    }
}