[英]Laravel insert to 3 related tables
嗨,大家好,我想知道是否有人尝试使用3个相关表将记录插入laravel中的表? 例
// Database Schema for Pharmacy
Schema::create('pharmacies', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->text('address');
});
// Relationship in App\Pharmacy table
public function pharmacists() {
return $this->hasMany('App\Pharmacist');
}
现在我有另一张桌子
Schema::create('pharmacists', function (Blueprint $table) {
$table->increments('id');
$table->integer('pharmacy_id')->unsigned()->index();
$table->foreign('pharmacy_id')->references('id')->on('pharmacies')->onDelete('cascade');
$table->string('fname');
});
// And this is the relationship in App\Pharmacist class
public function account() {
return $this->hasOne('App\Account');
}
public function pharmacy() {
return $this->belongsTo('App\Pharmacy');
}
现在第三张桌子
// This contain the foreign key for pharmacist_id
Schema::create('accounts', function (Blueprint $table) {
$table->increments('id');
$table->integer('pharmacist_id')->unsigned()->index();
$table->foreign('pharmacist_id')->references('id')->on('pharmacists')->onDelete('cascade');
$table->string('username')->unique();
});
// This is the relationship in App\Account class
public function pharmacists() {
return $this->belongsTo('App\Pharmacist');
}
现在,我尝试使用此代码在AccountsController下保存此代码
$input = Request::all();
$pharmacy = Pharmacy::create([
"name" => "Wendies Chicken",
"address" => "My Address",
]);
$pharmacists = new Pharmacist([
"fname" => "Administrator",
]);
$account = new Account([
"username" => "root",
]);
$pharmacists->account()->save($account);
$pharmacy->pharmacists()->save($pharmacists);
但是我说错了
Integrity constraint violation: 1048 Column 'pharmacist_id' cannot be null (SQL: insert into `accounts` (`username`, `pharmacist_id`, `updated_at`, `created_at`) values (root, 2015-08-09 05:13:31, 2015-08-09 05:13:31))
不知道如何保存,这只是一种节省。 我想将记录保存在3个相关表中。 有人可以帮我弄这个吗。 谢谢
尝试这个
$input = Request::all();
$pharmacy = Pharmacy::create([
"name" => "Wendies Chicken",
"address" => "My Address",
]);
$pharmacists = Pharmacist::create([
"pharmacy_id" => $pharmacy->id,
"fname" => "Administrator",
]);
$account = Account::create([
"pharmacist_id" => $pharmacists->id
"username" => "root",
]);
当您执行此代码时
$pharmacists->account()->save($account);
$pharmacy->pharmacists()->save($pharmacists);
实际上没有pharmacy_id
数据,所以是问题所在。 因此,您应该更改pharmacy_id
的架构,并将其值设置为default 0
$pharmacy = Pharmacy::create([
"name" => "Wendies Chicken",
"address" => "My Address",
]);
$pharmacy->pharmacists()->save([
"fname" => "Administrator",
]);
$pharmacy->pharmacists()->account()->save([
"username" => "root",
]);
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