[英]c# join XML files produce duplicates using Linq DefaultIfEmpty()
我正在尝试对两个XML文档使用leftOuterJoin,但是我当前使用的方式似乎从fileone返回了一些奇怪的重复部分(在下面的代码中进行了解释)。 我已经尝试了很多方法,但是却不知道该怎么做。 有人可以帮助解决这个问题吗? 提前谢谢了!
文件名:
<fileone>
<Book BookID="dog"> Dog </Book>
<Book BookID="cat"> Cat </Book>
</fileone>
文件二:
<filetwo>
<Edition BID="cat" OrderID="100"> about cat</Edition>
<Edition BID="cat" OrderID="200">more about cat</Edition>
</RightSeq>
我正在寻找的是(bookID = BID上的左外部联接):
<item>
<Book BookID="cat"> Dog </Book>
</item>
<item>
<Book BookID="cat"> Cat </Book>
<Edition BID="cat" OrderID="100"> about cat</Edition>
</item>
<item>
<Book BookID="cat"> Cat </Book>
<Edition BID="cat" OrderID="200"> more cat</Edition>
</item>
我的(错误的)代码:
var result = from a in fileone.Descendants()
join b in secondxdoc.Descendants()
on (string)a.Attribute("BookID") equal (string)b.Attribute("BID") into inners
from ele in inners.DefaultIfEmpty()
select new XElement("item", new XElement(a), ele == null ? null : new XElement(ele));
var output = new XElement("LeftOuterJoin", result);
}
当前错误的结果:
<item>
<fileone>
<Book BookID="dog"> Dog </Book> // this entire <fileone> bit is unwanted
<Book BookID="cat"> Cat </Book> //I don't know what I've done wrong
</fileone>
</item>
<item>
<Book BookID="cat"> Dog </Book>
</item>
<item>
<Book BookID="cat"> Cat </Book>
<Edition BID="cat" OrderID="100"> about cat</Edition>
</item>
<item>
<Book BookID="cat"> Cat </Book>
<Edition BID="cat" OrderID="200"> more cat</Edition>
</item>
多余的第一个<item>
元素是将根元素<fileone>
与第二个文件的后代结合在一起的结果。 如果要跳过根元素,请将fileone.Descendants()
替换为fileone.Root.Descendants()
:
var result = from a in fileone.Root.Descendants()
join b in secondxdoc.Descendants()
on (string)a.Attribute("BookID") equal (string)b.Attribute("BID") into inners
from ele in inners.DefaultIfEmpty()
select new XElement("item", a, ele);
var output = new XElement("LeftOuterJoin", result);
我没有使用传统的linq就得到了结果。 如果fileone在filetwo中没有匹配的项,则联接将不会给出结果。
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml; using System.Xml.Linq; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { string input1 = "<fileone>" + "<Book BookID=\\"dog\\"> Dog </Book>" + "<Book BookID=\\"cat\\"> Cat </Book>" + "</fileone>"; XDocument fileone = XDocument.Parse(input1); string input2 = "<filetwo>" + "<Edition BID=\\"cat\\" OrderID=\\"100\\"> about cat</Edition>" + "<Edition BID=\\"cat\\" OrderID=\\"200\\">more about cat</Edition>" + "</filetwo>"; XDocument secondxdoc = XDocument.Parse(input2); //<item> // <Book BookID="cat"> Dog </Book> //</item> //<item> // <Book BookID="cat"> Cat </Book> // <Edition BID="cat" OrderID="100"> about cat</Edition> //</item> //<item> // <Book BookID="cat"> Cat </Book> // <Edition BID="cat" OrderID="200"> more cat</Edition> //</item> XElement output = new XElement("Root"); foreach (XElement item in fileone.Descendants("Book")) { string bookId = item.Attribute("BookID").Value; List<XElement> bookTwoItems = secondxdoc.Descendants("Edition").Where(x => x.Attribute("BID").Value == bookId).ToList(); if (bookTwoItems.Count == 0) { XElement newItem = new XElement("item"); output.Add(newItem); newItem.Add(item); } else { foreach (XElement bookTwoItem in bookTwoItems) { XElement newItem = new XElement("item"); output.Add(newItem); newItem.Add(item); newItem.Add(bookTwoItem); } } } } } }
与左外部联接一起使用
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string input1 =
"<fileone>" +
"<Book BookID=\"dog\"> Dog </Book>" +
"<Book BookID=\"cat\"> Cat </Book>" +
"</fileone>";
XDocument fileone = XDocument.Parse(input1);
string input2 =
"<filetwo>" +
"<Edition BID=\"cat\" OrderID=\"100\"> about cat</Edition>" +
"<Edition BID=\"cat\" OrderID=\"200\">more about cat</Edition>" +
"</filetwo>";
XDocument secondxdoc = XDocument.Parse(input2);
//<item>
// <Book BookID="cat"> Dog </Book>
//</item>
//<item>
// <Book BookID="cat"> Cat </Book>
// <Edition BID="cat" OrderID="100"> about cat</Edition>
//</item>
//<item>
// <Book BookID="cat"> Cat </Book>
// <Edition BID="cat" OrderID="200"> more cat</Edition>
//</item>
var results = (from one in fileone.Descendants("Book")
join two in secondxdoc.Descendants("Edition") on one.Attribute("BookID").Value equals two.Attribute("BID").Value into inners
from two in inners.DefaultIfEmpty()
select new { fileone = one, filetwo = two == null ? null : two }).ToList();
XElement output = new XElement("Root");
foreach (var item in results)
{
XElement newItem = new XElement("item");
output.Add(newItem);
newItem.Add(item.fileone);
if (item.filetwo != null)
{
newItem.Add(item.filetwo);
}
}
}
}
}
还是这个方法
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string input1 =
"<fileone>" +
"<Book BookID=\"dog\"> Dog </Book>" +
"<Book BookID=\"cat\"> Cat </Book>" +
"</fileone>";
XDocument fileone = XDocument.Parse(input1);
string input2 =
"<filetwo>" +
"<Edition BID=\"cat\" OrderID=\"100\"> about cat</Edition>" +
"<Edition BID=\"cat\" OrderID=\"200\">more about cat</Edition>" +
"</filetwo>";
XDocument secondxdoc = XDocument.Parse(input2);
//<item>
// <Book BookID="cat"> Dog </Book>
//</item>
//<item>
// <Book BookID="cat"> Cat </Book>
// <Edition BID="cat" OrderID="100"> about cat</Edition>
//</item>
//<item>
// <Book BookID="cat"> Cat </Book>
// <Edition BID="cat" OrderID="200"> more cat</Edition>
//</item>
XElement output = new XElement("Root");
var results = (from one in fileone.Descendants("Book")
join two in secondxdoc.Descendants("Edition") on one.Attribute("BookID").Value equals two.Attribute("BID").Value into inners
from two in inners.DefaultIfEmpty()
select new { fileone = one, filetwo = two == null ? null : two })
.Select(x => x.filetwo == null ? new XElement("item", x.fileone) : new XElement("item", new object[] { x.fileone, x.filetwo }));
foreach (var item in results)
{
output.Add(item);
}
}
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.