实体框架Fluent API映射问题

Question

如何配置三个表之间的关系以获取所有相关数据？

我有以下模型（和数据库中的相同表）：

public class Client 
{
  public Guid ClientId { get; set; }
  public string FirstName { get; set; }

  public virtual ClientCard ClientCard { get; set; }
}

public class Card
{
  public Guid CardId { get; set; }
  public string Number { get; set; }

  public virtual ClientCard ClientCard { get; set; }
}

public class ClientCard
{
  public Guid ClientCardId { get; set; }
  public Guid CardId { get; set; }
  public Guid ClientId { get; set; }

  public virtual Client Client { get; set; }
  public virtual Card Card { get; set; }
}

以及以下OnModelCreating方法：

protected override void OnModelCreating(DbModelBuilder builder)
    {
        builder.Conventions.Remove<PluralizingTableNameConvention>();

        ...

        builder.Entity<ClientCard>()
            .HasKey(x => x.ClientCardId);

        builder.Entity<ClientCard>()
            .HasRequired(x => x.Client)
            .WithRequiredPrincipal(x => x.ClientCard);

        builder.Entity<ClientCard>()
            .HasRequired(x => x.Card)
            .WithRequiredPrincipal(x => x.ClientCard);

        base.OnModelCreating(builder);
    }

但是结果返回时没有相关数据。 为什么？

Answer 1

对于您的代码，请尝试以下操作：

public class Client 
{
  public Guid ClientId { get; set; }
  public string FirstName { get; set; }

  public virtual ICollection<ClientCard> ClientCard { get; set; }
}

public class Card
{
  public Guid CardId { get; set; }
  public string Number { get; set; }

  public virtual ICollection<ClientCard> ClientCard { get; set; }
}

public class ClientCard
{
  public Guid ClientCardId { get; set; }
  public Guid CardId { get; set; }
  public Guid ClientId { get; set; }

  public virtual Client Client { get; set; }
  public virtual Card Card { get; set; }
}

并映射：

    builder.Entity<Client>()
           .HasKey(t => t.ClinetID);
    ....
    builder.Entity<Client>()
           .HasMany(a => a.ClientCard)
           .WithRequired(p => p.Client)
           .HasForeignKey(p => p.ClientID);

对于卡

    ....
    builder.Entity<Card>()
           .HasMany(a => a.ClientCard)
           .WithRequired(p => p.Card)
           .HasForeignKey(p => p.CardID);

但我认为最好的方法是为每个实体创建一个单独的映射文件

Answer 2

现在，我使用以下模型：

public class Client 
{
   public Guid ClientId { get; set; }
   public string FirstName { get; set; }

   public Guid? CardId { get; set; }
   public virtual Card Card { get; set; }
}

public class Card
{
   public Guid CardId { get; set; }
   public string Number { get; set; }

   //public virtual Client Client { get; set; }
}

和以下OnModelCreating方法：

protected override void OnModelCreating(DbModelBuilder builder)
{
        builder.Conventions.Remove<PluralizingTableNameConvention>();

        ... 

        builder.Entity<Client>()
            .HasOptional(x => x.Card)
            //.WithOptionalPrincipal(x=> x.Client) 
            //or
            //.WithOptionalDependent(x=> x.Client)
            ;

        base.OnModelCreating(builder);
}

所有客户均返回相关数据（如果存在）。 但是，如果我想使用Card对象获取相关数据并且取消注释public virtual Client Client { get; set; } public virtual Client Client { get; set; } public virtual Client Client { get; set; }和WithOptionalPrincipal / WithOptionalDependent，我总是了解这些SqlException：“无效的列名'Client_ClientId'”（如果使用了WithOptionalPrincipal）或“无效的列名'Card_CardId'”（如果使用了WithOptionalDependent）

Answer 3

我终于找到了解决方案。

首先，我从Client类中删除了CardId。 其次，我更改了OnModelCreating方法：

protected override void OnModelCreating(DbModelBuilder builder)
    {
        builder.Conventions.Remove<PluralizingTableNameConvention>();

        ...

        builder.Entity<Client>()
            .HasOptional(x => x.Card)
            .WithOptionalDependent(x => x.Client)
            .Map(x => x.MapKey("CardId"))
            .WillCascadeOnDelete(false);

        builder.Entity<Card>()
            .HasOptional(x => x.Client)
            .WithOptionalPrincipal(x => x.Card)
            .WillCascadeOnDelete(false);

        base.OnModelCreating(builder);
    }