更新具有最小值sql的行

Question

我有这张桌子：

-----------------------
summonerId | timestamp
-----------------------
253222     | 14395235091096
929112     | 14395235091056
(...)

我想用更低的时间戳来更新行但我不能，当我这样做时

UPDATE summoners_shell 
SET 
summonerId = ".$s.",
timestamp = ".$time." 
WHERE timestamp = (SELECT MIN(timestamp))

它会更新所有行！ 为什么？ 我该怎么做我想要的？

Answer 1

当SELECT -subquery在WHERE -clause中时，它会锁定表，因此更新无法通过。 只需使用JOIN

UPDATE summoners_shell AS s1
JOIN (SELECT MIN(timestamp) AS mt FROM summoners_shell) AS mt ON (s1.timestamp = mt.mt)
SET 
    summonerId = ".$s.",
    timestamp = ".$time."

Answer 2

如果这不是拼写错误，则可能此查询将解决您的问题。

UPDATE summoners_shell 
    SET summonerId=".$s.",
    timestamp=".$time." 
WHERE timestamp=(
    SELECT MIN(timestamp)
    FROM 
    summoners_shell 
    )

Answer 3

 UPDATE summoners_shell SET summonerId=".$s.",timestamp=".$time." WHERE timestamp=(SELECT MIN(timestamp) FROM summoners_shell)

在子查询中添加：

FROM summoners_shell

Answer 4

试试这种方式

UPDATE summoners_shell SET summonerId=".$s.",timestamp=".$time."
     WHERE timestamp=(SELECT MIN(timestamp) from summoners_shell)