[英]How to use Pivot on two columns in sql
我的表格中有以下数据。 标志位,标签为varchar。
parentid code label flag
1 abc hello false
1 xyz bye false
1 qrt hi true
我需要提取记录为
parentid label_abc flag_abc label_xyz flag_xyz label_qrt flag_qrt
我现在只能使用Pivot来获取标签,但是当我为标志提供第二个聚合函数时,它将给出错误(“,”附近的语法不正确)。 有没有办法使用Pivot来获取两列。
我做了这样的事情:
SELECT distinct
parentid
, [abc] as label_abc
, [xyz] as label_xyz
, [qrt] as label_qrt
FROM (
Select
parentid,
label,code
FROM items
) a
Pivot (
Max(label), max (flag)
FOR code in ([abc], [xyz], [qrt]
) as Pvt
我发现使用pivot
运算符执行此操作有些棘手,而使用条件聚合则容易得多:
select
parentid,
max(case when code = 'abc' then label end) as label_abc,
max(case when code = 'abc' then flag end) as flag_abc,
max(case when code = 'xyz' then label end) as label_xyz,
max(case when code = 'xyz' then flag end) as flag_xyz,
max(case when code = 'qrt' then label end) as label_qrt,
max(case when code = 'qrt' then flag end) as flag_qrt
from (
select parentid, code, label, cast(flag as int) flag
from items
) src
group by parentid;
是的,但需要分别进行调整。 它需要花哨的步法,但看起来应该更像:
select distinct parentid
, [abc1] as label_abc
, [xyz1] as label_xyz
, [qrt1] as label_qrt
, [abc2] as flag_abc
, [xyz2] as flag_xyz
, [qrt2] as flag_qrt
from (
select parentid
, label
, label + '1' as code1
, label + '2' as code2
from items
) as a
pivot (
max(label) for code1 in ([abc1], [xyz1], [qrt1])
) as pvt1
pivot (
max(flag) for code2 in ([abc2], [xyz2], [qrt2])
) as pvt2
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