console.log和JSON.parse返回错误

Question

我正在尝试解析JSON字符串并将其记录到Chrome控制台。 该字符串使用JSONLint进行验证。 为什么Chrome会返回错误：“未捕获的SyntaxError：意外的令牌％”？

<script>console.log(JSON.parse('{"header-top":{"name":"Header Top","id":"header-top","description":"","class":"","before_widget":"\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E","after_widget":"\u003C\/li\u003E\n","before_title":"\u003Ch2 class=\u0022widgettitle\u0022\u003E","after_title":"\u003C\/h2\u003E\n"}}'));</script>

这是JSON，Pretty Printed：

{
    "header-top": {
        "name": "Header Top",
        "id": "header-top",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "header": {
        "name": "Header",
        "id": "header",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "header-bottom": {
        "name": "Header Bottom",
        "id": "header-bottom",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "content-top": {
        "name": "Content Top",
        "id": "content-top",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "content": {
        "name": "Content",
        "id": "content",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "content-bottom": {
        "name": "Content Bottom",
        "id": "content-bottom",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "footer-top": {
        "name": "Footer Top",
        "id": "footer-top",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "footer": {
        "name": "Footer",
        "id": "footer",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    },
    "footer-bottom": {
        "name": "Footer Bottom",
        "id": "footer-bottom",
        "description": "",
        "class": "",
        "before_widget": "\u003Cli id=\u0022%1$s\u0022 class=\u0022widget %2$s\u0022\u003E",
        "after_widget": "\u003C\/li\u003E\n",
        "before_title": "\u003Ch2 class=\u0022widgettitle\u0022\u003E",
        "after_title": "\u003C\/h2\u003E\n"
    }
}

Answer 1

发生这种情况是因为您的一个字符串中有"字符。

它的问题在于，当评估字符串文字（长JSON）时，它会被替换为" （引号字符），这会导致某些JSON字符串损坏：

"\u0022"

变成

"""

因此，从技术上讲，给定的JSON是有效的JSON，但不能在评估\\uXXXX序列的环境中按原样使用。

因此，例如，您可以从其他来源读取它-例如作为AJAX请求的响应，但是您不能将其用作JS代码中的字符串文字。