SQL按日期排序的总和

Question

我应该知道这一点，但由于某种原因，这让我感到困惑。

这个简单的代码按天输出所有订单

USE [K.1]
Select CreatedAt,Identifier,RoundedPriceSum from StarOrder
where SiteID = 1
and OrderType <>2
and CreatedAt between '2015/01/01' and '2015/08/20'

CreatedAt是一个日期，Identifier是唯一的订单ID，RoundedPriceSum是订单的总数。

是否可以修改代码以每天提供总计RoundedPriceSum_

Answer 1

使用GROUP BY ：

Select cast(CreatedAt as date) as CreatedDay, SUM(RoundedPriceSum)
from StarOrder so
where SiteID = 1 and OrderType <> 2 and
      CreatedAt >= '2015-01-01' and
      CreatedAt < '2015/08/20'
group by cast(CreatedAt as date)
order by CreatedDay;

有关查询更改的注意事项：

• 将日期更改为ISO标准YYYY-MM-DD格式。
• 将BETWEEN替换为>=和< 。 这样可以更好地处理带日期的日期。
• 使用cast(as date)删除时间部分。
• 添加了ORDER BY因此结果按天排列。

Answer 2

select s.CreatedAt,s.Identifier,x.tot
from StarOrder s
join 
(select CreatedAt,sum(RoundedPriceSum) as tot
from StarOrder
where SiteID = 1
and OrderType <>2
and CreatedAt between '2015/01/01' and '2015/08/20'
group by createdat) x
on x.createdat = s.createdat
where SiteID = 1
and OrderType <>2
and s.CreatedAt between '2015/01/01' and '2015/08/20'