如何在JavaScript中合并具有相同值的JSON数组

Question

我有两个数组，我想合并具有相同值的数据

"calleridnum":"0090000163", "uid":"0090000163",

这是我的第一个数组：

[
{
"_id":"55d44fe38879f12e6431c23c",
"event":"ConfbridgeJoin",
"channel":"SIP/peer_voip301confbridge-00000145",
"uniqueid":"1439977429.777",
"conference":"0090000167",
"calleridnum":"0090000163",
"calleridname":"0090000163",
"__v":0,
"sipSetting":{
"accountcode":"",
"accountcode_naisen":"202",
"extentype":0,
"extenrealname":"",
"name":"0090000163",
"secret":"Myojyo42f!",
"username":"0090000163",
"context":"innercall_xdigit",
"gid":101,
"cid":"0090000007"
}
}
]

这是我的第二个数组

[
{
"id":8,
"uid":"0090000163",
"cid":"0090000007",
"extension":"202",
"secret":"Myojyo42f!",
"leader":true,
"simultaneous":false,
"confbridge_id":6,
"created_at":"2015-08-18 09:22:20",
"updated_at":"2015-08-18 09:22:20"
},
{
"id":15,
"uid":"0090000164",
"cid":"0090000007",
"extension":"203",
"secret":"Myojyo42f!",
"leader":false,
"simultaneous":false,
"confbridge_id":6,
"created_at":"2015-08-19 01:26:30",
"updated_at":"2015-08-19 01:26:30"
}
]

我想合并具有相同值0090000163的对象

我想获得如果calleridnum == uid

我想得到这个输出

"_id":"55d44fe38879f12e6431c23c",
    "event":"ConfbridgeJoin",
    "channel":"SIP/peer_voip301confbridge-00000145",
    "uniqueid":"1439977429.777",
    "conference":"0090000167",
    "calleridnum":"0090000163",
    "calleridname":"0090000163",
    "__v":0,
    "sipSetting":{
    "accountcode":"",
    "accountcode_naisen":"202",
    "extentype":0,
    "extenrealname":"",
    "name":"0090000163",
    "secret":"Myojyo42f!",
    "username":"0090000163",
    "context":"innercall_xdigit",
    "gid":101,
    "cid":"0090000007"
    "id":8,
    "uid":"0090000163",
    "cid":"0090000007",
    "extension":"202",
    "secret":"Myojyo42f!",
    "leader":true,
    "simultaneous":false,
    "confbridge_id":6,
    "created_at":"2015-08-18 09:22:20",
    "updated_at":"2015-08-18 09:22:20"

我在php中做。 但我对javascript没有太多了解

这是我在php中的代码

// $apiResults['participants'] == first array
// $apiResults['conference_participants'] == second array


$conf_participants = array();
      foreach($apiResults['participants'] as $participant)
      {
       foreach($apiResults['conference_participants'] as $conference_participant)
         {
    if($participant['calleridnum'] == $conference_participant['uid'])
        {

           $conf_participants['uniqueid'] = $participant['uniqueid'];
           $conf_participants['event'] = $participant['event'];
           $conf_participants['channel'] = $participant['channel'];
           $conf_participants['uid'] = $conference_participant['uid'];



       }
       }
      }

Answer 1

假设您有对象arr1和arr2两个数组，您需要遍历两个数组，比较arr1的值calleridnum和arr2 uid （如果它们相同），然后将对象合并到in arr1 。

for(var i in arr1){
for (var j in arr2)
   if (arr2[j].uid == arr1[i].calleridnum ) {
    $.extend(arr1[i], arr2[j]);
       break;
   }
}