[英]Merging two mysql queries from different databases in PHP
我需要将来自分别位于不同服务器上的两个数据库的一对MySQL查询合并到一个多维关联数组中。 以下是我正在处理的数据的示例。
问题似乎与缺少唯一键(理想情况下是相应的“ sku”值)以用作合并数据的索引的$ data0数组值有关。
所需的输出将是:
Array (
[0] => Array (
[SKU] => 101
[Description] => Test Item 1
[On Hand 1] => 3
[On Hand 2] => 7
)
[1] => Array (
[SKU] => 102
[Description] => Test Item 2
[On Hand 1] => 11
[On Hand 2] => 15
)
)
可能有更好的方法来处理MySQL查询和所需的数组。 如果是这样,请告诉我。 我是高级初学者,请提供任何反馈意见,我们将竭尽所能。 谢谢!
<?
$query1 = "SELECT sku, description, on_hand as 'On Hand 1' FROM database1"
$queryresult1 = mysql_query($query1, $connection1);
$data1 = array();
while ($resultrow1 = mysql_fetch_assoc($queryresult1)) {
array_push($data1, $resultrow1);
}
$query2 = "SELECT sku, on_hand as 'On Hand 2' FROM database2"
$queryresult2 = mysql_query($query2, $connection2);
$data2 = array();
while ($resultrow2 = mysql_fetch_assoc($queryresult2)) {
array_push($data2, $resultrow2);
}
$data0 = array_merge($data1, $data2);
//example code for troubleshooting
$data1 = array('101' => array('SKU' => '101', 'Description' => 'Test Item 1', 'On Hand 1' => 3), '102' => array('SKU' => '102', 'Description' => 'Test Item 2', 'On Hand 1' => 11));
print_r($data1);
echo "<br /><br />";
$data2 = array('101' => array('SKU' => '101', 'On Hand 2' => 7), '102' => array('SKU' => '102', 'On Hand 2' => 15));
print_r($data2);
echo "<br /><br />";
$data0 = array_merge($data1, $data2);
print_r($data0);
?>
使用一个UNION
查询可能会更好:
SELECT sku, description, on_hand as 'On Hand 1' FROM database1
UNION ALL
SELECT sku, null , on_hand as 'On Hand 2' FROM database2
注意, database2
查询中的description字段使用null
。 UNION成员查询必须具有相同的列数和相同的类型。
然后,这很简单:
while($row = mysql_fetch_assoc($result)) {
$data[] = $row;
}
不需要两个查询,两个提取循环和一个以后的合并。
您可以通过使用JOIN
语法将查询中的两个表JOIN
来做到这一点: https : //dev.mysql.com/doc/refman/5.0/en/join.html
因此,您的查询将如下所示:
SELECT
table1.sku,
table1.description,
table1.on_hand as 'On Hand 1',
table2.on_hand as 'On Hand 2'
FROM
database1.table1 JOIN
database2.table2 ON table1.sku = table2.sku
来自两个表的行将彼此连接,其中sku字段值彼此对应。 如果希望从table1和table2获得所有结果,则可以进行LEFT JOIN
。
<?php
// connection 1
$connection1= mysql_connect("localhost","root","");
//selecting database 1
mysql_select_db("database1",$connection1);
// select query from the database1 and table 1
$query1 = "SELECT sku, description, on_hand as 'On Hand 1' FROM database1.table1";
$queryresult1 = mysql_query($query1, $connection1);
$data1 = array();
while ($resultrow1 = mysql_fetch_assoc($queryresult1)) {
array_push($data1, $resultrow1);
}
//connection 1
$connection2= mysql_connect("localhost","root","");
//selecting database 2
mysql_select_db("database2",$connection2);
// select query from the database2 and table 2
$query2 = "SELECT sku, on_hand as 'On Hand 2' FROM database2.table2";
$queryresult2 = mysql_query($query2, $connection2);
$data2 = array();
while ($resultrow2 = mysql_fetch_assoc($queryresult2)) {
array_push($data2, $resultrow2);
}
$data0 = array_merge($data1, $data2);
print_r($data0);
?>
通过循环遍历$data1
每个键,可以使用当前$key
从$data2
检索值。 这将为您提供所需的结果:
$data1 = array('101' => array('SKU' => '101', 'Description' => 'Test Item 1', 'On Hand 1' => 3), '102' => array('SKU' => '102', 'Description' => 'Test Item 2', 'On Hand 1' => 11));
$data2 = array('101' => array('SKU' => '101', 'On Hand 2' => 7), '102' => array('SKU' => '102', 'On Hand 2' => 15));
$data0 = array();
foreach($data1 as $key => $data){
$data['On Hand 2'] = $data2[$key]['On Hand 2'];
$data0[] = $data;
}
unset($data1, $data2);
print_r($data0);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.