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[英]How to show first post content and links for older post only in WordPress
[英]How to show only the first row of a post?
好的,下面的代码工作正常。 除了我给用户最多下载了4张图片外,产品预览页应该只显示其中一张图片,例如产品页面中数组中的第一个图片,但是如果用户上传了4张图片,它将显示所有行。 我该如何限制呢? 谢谢。
<?php
echo 'Your posts:' . '<br>' . '<hr>';
$posts = "SELECT * FROM posts,image_data WHERE userid='$user' AND user_posts.userid = image_data.client_id ORDER BY date_created ASC";
$posts_result = $mysqli->query($posts);
while ($posts_result_rows = $posts_result->fetch_assoc()) {
$its_id = $posts_result_rows["userid"];
$its_title = $posts_result_rows['post_title'];
$its_image = $posts_result_rows['file'];
$its_description = $posts_result_rows['post_description'];
?>
<table border=0 cellpadding=5 cellspacing=0 >
<tr>
<?php echo '<br>' . $its_title . ' <br>' . $its_description . '<br>'; ?>
<img src="<?php echo "users_data/users_posted_data/".$its_image; ?>" alt="<?php echo $its_title; ?>" width="120" height="120"><hr>
</tr>
</table>
<?php
}
?>
按降序排列以获得最新行
$posts = "select * from (SELECT * FROM posts,image_data WHERE userid='$user' AND posts.userid = image_data.client_id ORDER BY date_created DESC)temp group by userid ";
$posts_result = $mysqli->query($posts);
下面提到的SQL查询工作正常: http : //sqlfiddle.com/#!9/1a0e9/1
select * from
(SELECT * FROM posts,image_data WHERE userid=1
AND posts.userid = image_data.client_id
ORDER BY date_created DESC)temp group by userid;
尝试添加LIMIT 1
$posts = "SELECT * FROM posts,image_data WHERE userid='$user' AND user_posts.userid = image_data.client_id ORDER BY date_created ASC LIMIT 1";
$posts_result = $mysqli->query($posts);
<?php
echo 'Your posts:<br><hr>';
$posts = "SELECT * FROM posts,image_data WHERE userid='$user' AND user_posts.userid = image_data.client_id ORDER BY date_created ASC";
$posts_result = $mysqli->query($posts);
while ($posts_result_rows = $posts_result->fetch_assoc()) {
$its_id = $posts_result_rows["userid"];
$its_title = $posts_result_rows['post_title'];
$its_image = $posts_result_rows['file'];
$its_description = $posts_result_rows['post_description'];
echo "<table border=0 cellpadding=5 cellspacing=0 ><tr><td>";
echo '<br>' . $its_title . ' <br>' . $its_description . '<br>';
}
?>
<img src="<?php echo "users_data/users_posted_data/".$its_image; ?>" alt="<?php echo $its_title; ?>" width="120" height="120"><hr>
</td></tr>
</table>
$posts = "SELECT * FROM posts WHERE userid='$user' ORDER BY date_created ASC";
$posts_result = $mysqli->query($posts);
while ($posts_result_rows = $posts_result->fetch_assoc())
{
$posts1 = "SELECT * FROM image_data WHERE client_id='$user' and file != '' ORDER BY image_id DESC";
$posts_result1 = $mysqli->query($posts1);
$posts_result_rows1 = $posts_result1->fetch_assoc()
$its_id = $posts_result_rows["userid"];
$its_title = $posts_result_rows['post_title'];
$its_image = $posts_result_rows1['file'];
$its_description = $posts_result_rows['post_description'];
?>
<table border=0 cellpadding=5 cellspacing=0 >
<tr>
<td>
<?php echo '<br>' . $its_title . ' <br>' . $its_description . '<br>'; ?>
<img src="<?php echo "users_data/users_posted_data/".$its_image; ?>" alt="<?php echo $its_title; ?>" width="120" height="120" />
<hr>
</td>
</tr>
</table>
<?php
}
?>
第二个图像查询在while循环内写入,以仅获取一个图像并检查文件列是否为空。 不知道您的列名是什么,将您的列名放在表结构中。
重要的部分是增加limit 1
。
SELECT * FROM posts,image_data WHERE userid='$user' AND user_posts.userid = image_data.client_id ORDER BY date_created ASC limit 1
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