如何在活动（而不是新的浏览器）中打开URL？

Question

谁能帮助我检查我的代码，以查看为什么无法在应用程序本身中启动它，但将我定向到浏览器吗？ ）： 谢谢！！

主要活动

package com.intelligami.androidwebviewapp;

import android.app.ActionBar;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.webkit.WebSettings;
import android.webkit.WebView;
import android.widget.ShareActionProvider;


public class MainActivity extends Activity {

private WebView mWebView;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    mWebView = (WebView) findViewById(R.id.activity_main_webview);
    WebSettings webSettings = mWebView.getSettings();
    webSettings.setJavaScriptEnabled(true);
    mWebView.loadUrl("http://intelligami.com/submitqn");
    mWebView.setWebViewClient(new com.intelligami.androidwebviewapp.MyAppWebViewClient(){
        @Override
        public void onPageFinished(WebView view, String url) {
            //hide loading image
            findViewById(R.id.progressBar1).setVisibility(View.GONE);
            //show webview
            findViewById(R.id.activity_main_webview).setVisibility(View.VISIBLE);
        }});


}
private class MyWebViewClient extends MyAppWebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        view.loadUrl(url);
        return true;
    }
}
@Override
public void onBackPressed() {
    if(mWebView.canGoBack()) {
        mWebView.goBack();
    } else {
        super.onBackPressed();
    }
}


private ShareActionProvider mShareActionProvider;
@Override
public boolean onCreateOptionsMenu(Menu menu) {

    /** Inflating the current activity's menu with res/menu/items.xml */
    getMenuInflater().inflate(R.menu.menu_main, menu);

    /** Getting the actionprovider associated with the menu item whose id is share */
    mShareActionProvider = (ShareActionProvider) menu.findItem(R.id.share).getActionProvider();

    /** Setting a share intent */
    mShareActionProvider.setShareIntent(getDefaultShareIntent());

    return super.onCreateOptionsMenu(menu);

}

/** Returns a share intent */
private Intent getDefaultShareIntent(){
    Intent intent = new Intent(Intent.ACTION_SEND);
    intent.setType("text/plain");
    intent.putExtra(Intent.EXTRA_SUBJECT, "Convert Website to Android Application");
    intent.putExtra(Intent.EXTRA_TEXT," Vist www.AndroidWebViewApp.com if you Want to Convert your Website or Blog to Android Application");
    return intent;
}


}

我的应用查看客户端。 爪哇

package com.intelligami.androidwebviewapp;

import android.content.Intent;
import android.net.Uri;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class MyAppWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
    if(Uri.parse(url).getHost().endsWith("intelligami.com/submitqn")) {
        return false;
    }

    Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
    view.getContext().startActivity(intent);
    return true;
}
}

错误在哪里？ ：D

它一直在浏览器中打开。

Answer 1

在以下行中：

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));

您要求Android使用意图常量ACTION_VIEW打开ACTION_VIEW因此它默认为外部浏览器。

这里是一个完整的示例（ 从此处获取 ），显示了如何使用WebViewClient打开URL：

package com.paresh.webviewclientdemo;

import android.app.Activity;
import android.graphics.Bitmap;
import android.os.Bundle;
import android.view.KeyEvent;
import android.webkit.WebView;
import android.webkit.WebViewClient;

/*
 * Demo of creating an application to open any URL inside the application and clicking on any link from that URl
should not open Native browser but  that URL should open in the same screen.
 */
public class WebViewClientDemoActivity extends Activity {
    /** Called when the activity is first created. */

    WebView web;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        web = (WebView) findViewById(R.id.webview01);
        web.setWebViewClient(new myWebClient());
        web.getSettings().setJavaScriptEnabled(true);
        web.loadUrl("http://www.google.com");
    }

    public class myWebClient extends WebViewClient
    {
        @Override
        public void onPageStarted(WebView view, String url, Bitmap favicon) {
            // TODO Auto-generated method stub
            super.onPageStarted(view, url, favicon);
        }

        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            // TODO Auto-generated method stub

            view.loadUrl(url);
            return true;

        }
    }

    // To handle "Back" key press event for WebView to go back to previous screen.
   @Override
   public boolean onKeyDown(int keyCode, KeyEvent event)
  {
    if ((keyCode == KeyEvent.KEYCODE_BACK) && web.canGoBack()) {
        web.goBack();
        return true;
    }
    return super.onKeyDown(keyCode, event);
   }
}