JSON发送到服务器

Question

我必须从我的Android应用程序向服务器发送一些JSON数据。

这是我编写的代码。

public static String POST(String url, String id, int status, String cardno,String orderno){
    InputStream inputStream = null;
    String result = "";

    try {

        // 1. create HttpClient
        HttpClient httpclient = new DefaultHttpClient();
        HttpConnectionParams.setConnectionTimeout(httpclient.getParams(), 10000);
        // 2. make POST request to the given URL
        HttpPost httpPost = new HttpPost(url);

        String json = "";

        // 3. build jsonObject
        JSONObject jsonObject = new JSONObject();
        jsonObject.put("order_number", orderno);
        jsonObject.put("id", id);
        jsonObject.put("status", status);
        jsonObject.put("card_no", cardno);

        JSONArray postjson=new JSONArray();
        postjson.put(jsonObject);


        // 4. convert JSONObject to JSON to String
       // json = jsonObject.toString();
       // httpPost.setParams("json", json.toString());
        System.out.println("json is"+jsonObject.toString());
        httpPost.getParams().setParameter("jsonpost", postjson);

        // 5. set json to StringEntity
        StringEntity se = new StringEntity(json);

        // 6. set httpPost Entity
        se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,
                "application/json"));
        httpPost.setEntity(se);



        // 8. Execute POST request to the given URL
        HttpResponse httpResponse = httpclient.execute(httpPost);

        // 9. receive response as inputStream
        inputStream = httpResponse.getEntity().getContent();

        // 10. convert inputstream to string
        if(inputStream != null)
            result = convertInputStreamToString(inputStream);
        else
            result = "Did not work!";

    } catch (Exception e) {
        Log.d("InputStream", e.getLocalizedMessage());
    }

    // 11. return result
    System.out.println("result is"+result);
    return result;
}


private static String convertInputStreamToString(InputStream inputStream) throws IOException{
    BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
    String line = "";
    String result = "";
    while((line = bufferedReader.readLine()) != null)
        result += line;

    inputStream.close();
    return result;

}

而在文本文件中接收此内容的php脚本为：

<?php

error_reporting(E_ALL & ~E_NOTICE);
    file_put_contents("postData.txt",$_REQUEST);

    if(isset($_REQUEST['jsonpost']))
    {
        echo 'passed';
    }else{
        echo "NOT RUNNING";
    }
    exit;
?>

当我从android应用程序执行代码时，我的请求已完成以连接到服务器，但无法在文本文件中获取任何数据。

我想念什么？ 我应该如何将数据发送到服务器？ 错误是在我的android代码中发送数据还是在php脚本中接收了数据？

我将修改后的代码如下：

 public static String POST(String url, String id, int status, String cardno,String orderno){
        InputStream inputStream = null;
        String result = "";

        try {

            HttpClient httpclient = new DefaultHttpClient();
            HttpConnectionParams.setConnectionTimeout(httpclient.getParams(), 10000);
            HttpPost httpPost = new HttpPost(url);
            String json = "";
            JSONObject jsonObject = new JSONObject();
            jsonObject.put("order_number", orderno);
        jsonObject.put("id", id);
        jsonObject.put("status", status);
        jsonObject.put("card_no", cardno);
        JSONArray postjson=new JSONArray();
        postjson.put(jsonObject);
        StringEntity se = new StringEntity(jsonObject.toString());
        httpPost.setEntity(se);
        httpPost.setHeader("Accept", "application/json");
        httpPost.setHeader("Content-type", "application/json");
        ResponseHandler responseHandler = new BasicResponseHandler();
        HttpResponse httpResponse = httpclient.execute(httpPost);
        inputStream = httpResponse.getEntity().getContent();
        if(inputStream != null)
            result = convertInputStreamToString(inputStream);
        else
            result = "Did not work!";

    } catch (Exception e) {
        Log.d("InputStream", e.getLocalizedMessage());
    }
    System.out.println("result is"+result);
    return result;
    }

    private static String convertInputStreamToString(InputStream inputStream) throws IOException{
        BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
        String line = "";
        String result = "";
        while((line = bufferedReader.readLine()) != null)
            result += line;
        inputStream.close();
        return result;
    }

但这仍然行不通。 在我的php脚本中要进行任何更改吗？

Answer 1

尝试将您的帖子数据设置为这样的请求：

//passes the results to a string builder/entity
StringEntity se = new StringEntity(jsonObject.toString());

//sets the post request as the resulting string
httpPost.setEntity(se);

//sets a request header so the page receving the request
//will know what to do with it
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");

//Handles what is returned from the page 
ResponseHandler responseHandler = new BasicResponseHandler();
HttpResponse httpResponse = httpclient.execute(httpPost, responseHandler);

请注意，这不是完整的代码，只是补充代码的部分，因此请在您的示例中使用它（所有var的名称都与您命名的名称相同，因此应该很容易:)）。

另外，还要确保您的JSONObject已经jsonpost关键，因为当你将它张贴这样， key->values从JSONObject的将成为key->values在$_POST变量。

Answer 2

$_REQUEST是一个类似于$_POST & $_GET的数组，因此假设您只是想知道那里有什么，而无需经过任何形式的优雅显示print_r()

file_put_contents("postData.txt",print_r($_REQUEST, true));