[英]Deserialize List of object Json with Gson
我有下一个杰森:
{"total":1,"min":20,"sort":"","count":20,"houses":[{"logo":"house1.jpg","name":"Springfield","age":100}]
下一个类是House:
public class House{
private String logo;
private String name;
private int age;
}
我想获得众议院名单。 我尝试了下一个代码:
Gson gson = new Gson();
List<House> rest = gson.fromJson(JsonString, new TypeToken<List<House>>(){}.getType());
但是它不起作用,程序卡住了。
提前致谢
如果我是你,我会创建一个新类,例如:
public class YourNewObject
{
private int total;
private int min;
private int count
private List<House> houses;
}
然后使用:
Gson gson = new Gson();
YourNewObject houses = gson.fromJson(JsonString, YourNewObject.class);
那应该工作。
问候
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