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mysql 查询中的 1:N 实现

[英]1:N implementation in mysql query

假设表state_info 2 列。

state       |  district
------------+---------------
Karnataka   |  Bangalore
Karnataka   |  Belgium
Karnataka   |  Mysore
Mumbai      |  Sandra
Mumbai      |  Madeira

我想在单列中输出它们

Karnataka
Bangalore
Belgium
Mysore

Mumbai
Sandra
Madeira

状态低于其 dist ,再次状态低于其 dist

SELECT CONCAT(state, ', ', district) FROM state_info;

要得到

Karnataka, Bangalore
Karnataka, Belgium
Karnataka, Mysore
Mumbai, Sandra
Mumbai, Madeira

你可以这样做

Select Distinct(state) from Table1
UNION 
Select Distinct(district) from Table1;

结果将是

Bangalore
Belgium
Mysore
Sandra
Madeira
Karnataka
Mumbai
select * from (
 Select Distinct(state) as data from Table1
 UNION 
 Select Distinct(district) as data from Table1;
) order by  data  

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