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[英]How to consume Spring HATEOAS REST resources containing links to another resources?
[英]REST HATEOAS: How to serialize nested resources (with Spring HATEOAS)?
我使用Spring HATEOAS在我的应用程序中创建REST HATEOAS API。 到目前为止,它运行良好,但是在嵌套资源方面我还是很困惑。 将这样的类层次结构映射到REST HATEOAS资源的正确方法是:
public class MyEntity {
private int id;
private List<ChildEntity> children;
}
public class ChildEntity {
private int id;
private AnotherEntity entity;
}
public class AnotherEntity {
}
我为所有这些实体创建了Resource类,但是在序列化MyEntity时,所有包含的实体都被序列化为POJO,尽管我也需要将它们序列化为资源(带有链接等)。 有没有一种方法可以将资源添加到父资源(而不使用Resources类)? 还是我必须向孩子添加@JsonIgnore,然后在ResourceAssembler中手动将孩子添加为资源? 那么使用ResourceSupport而不是Resource更有意义吗?
扩展ResourceSupport:
public class MyEntityResource extends ResourceSupport {
private int identificator;
private List<ChildEntityResource> children;
public int getIdentificator() {
return identificator;
}
public void setIdentificator(int id) {
this.identificator = identificator;
}
public List<ChildEntityResource> getChildren() {
return children;
}
public void setChildren(List<ChildEntityResource> children) {
this.children = children;
}
}
public class ChildEntityResource extends ResourceSupport {
private int identificator;
private AnotherEntityResource entity;
public int getIdentificator() {
return identificator;
}
public void setIdentificator(int identificator) {
this.identificator = identificator;
}
public AnotherEntityResource getEntity() {
return entity;
}
public void setEntity(AnotherEntityResource entity) {
this.entity = entity;
}
}
public class AnotherEntityResource extends ResourceSupport {
private String value;
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
}
@RestController
public class EntityController {
@RequestMapping(value = "/entity", method = RequestMethod.GET)
public ResponseEntity<MyEntityResource> index() {
AnotherEntityResource anotherEntityResource = new AnotherEntityResource();
anotherEntityResource.add(new Link("link-for-another-entity-resource", "rel-1"));
anotherEntityResource.setValue("value for Another Entity","rel-2");
ChildEntityResource childEntityResource = new ChildEntityResource();
childEntityResource.setIdentificator(20);
childEntityResource.setEntity(anotherEntityResource);
childEntityResource.add(new Link("link-for-child-entity-resource", "rel-3"));
MyEntityResource entityResource = new MyEntityResource();
entityResource.setIdentificator(100);
entityResource.setChildren(Arrays.asList(childEntityResource));
entityResource.add(new Link("link-for-entity-resource"));
return new ResponseEntity<MyEntityResource>(entityResource, HttpStatus.OK);
}
}
@SpringBootApplication
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
结果是:
{
"identificator": 100,
"children": [
{
"identificator": 20,
"entity": {
"value": "value for Another Entity",
"_links": {
"rel-1": {
"href": "link-for-another-entity-resource"
}
}
},
"_links": {
"rel-2": {
"href": "link-for-child-entity-resource"
}
}
}
],
"_links": {
"rel-3": {
"href": "link-for-entity-resource"
}
}
}
但是您必须考虑这是否是连接不同资源的正确选择。 除非您在控制器中提供方法来获取此嵌入式资源,否则您将无法单独访问它们。 一种解决方案是使用HAL。 使用HAL,您可以使用_links属性指向资源,也可以将此资源嵌入_embedded属性。
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