PHP-基于相同键的循环和合并数组

Question

foreach ($total_month_hours_result as $key => $data){ print_r($data); } //outputs below array

Array
(
    [0] => Array
        (
            [SITE_STATUS] => Offshore
            [ACTUAL_HOURS] => 176
            [MONTH_YEAR] => APR-2015
        )

    [1] => Array
        (
            [SITE_STATUS] => Onsite
            [ACTUAL_HOURS] => 180
            [MONTH_YEAR] => APR-2015
        )

)

再次循环数组

foreach ($data as $key => $val ){print_r($val);} // outputs below array


Array
(
    [SITE_STATUS] => Offshore
    [ACTUAL_HOURS] => 176
    [MONTH_YEAR] => APR-2015
)

Array
(
    [SITE_STATUS] => Onsite
    [ACTUAL_HOURS] => 180
    [MONTH_YEAR] => APR-2015
)

尝试以下代码

$hours_array = Array();
foreach ($project_months as $month) {

    foreach ($total_month_hours_result as $key => $data){

        if (!empty($data)){

            foreach ($data as $key => $val ){

                if ($val['MONTH_YEAR'] == $month ){

                  $hours_array[$val['MONTH_YEAR']][$month]['SITE_STATUS'] = $val['SITE_STATUS'];
                  $hours_array[$val['MONTH_YEAR']][$month]['OFFSHORE_HOURS'] = $val['OFFSHORE_HOURS'];
                  $hours_array[$val['MONTH_YEAR']][$month]['ONSITE_HOURS'] = $val['ONSITE_HOURS'];
                  $hours_array[$val['MONTH_YEAR']][$month]['TOTAL_HOURS'] = $val['ONSITE_HOURS'] + $val['OFFSHORE_HOURS'];

                }
            }
        }
    }
}

产出

Array
(
    [APR-2015] => Array
        (
            [APR-2015] => Array
                (
                    [SITE_STATUS] => Onsite
                    [TOTAL_HOURS] => 356
                    [ONSITE_HOURS] => 180
                    [OFFSHORE_HOURS] => 176
                )

        )       
)

基于关键的month_year我如何将两个数组合并为以下输出

Array
(
    [SITE_STATUS] => Offshore
    [ACTUAL_HOURS] => 176
    [SITE_STATUS] => Onsite
    [ACTUAL_HOURS] => 180
    [MONTH_YEAR] => APR-2015
)

编辑

我实际上想要实现的是以下面的表格形式显示“现场”，“离岸时间”和“总工时”

它确实正确显示了首次APR-2015的小时数，但没有正确显示JUN-15的小时数

Name of Engineer    Site  MAR-15  Site    APR-15  Site     JUN-15
User 1                            Onsite   120    Offshore  170              
User 2                            Offshore 140    Offshore  180

Total Hours                                260                                          350
Total Onsite                               120                                          0
Total Offshore                             140                                          350

SQL：

SELECT  decode(pr.siteid,   397,   'Onsite',   398,   'Offshore') AS
site_status,
  SUM(tm.user_hours) AS
actual_hours,
  tm.month_year
FROM project_resource pr
INNER JOIN monthly_table tm ON tm.resource_id = pr.employeeid
 AND tm.project_id = pr.projectid
INNER JOIN resource_table rd ON rd.employeeid = pr.employeeid
INNER JOIN expband_view exbvw ON exbvw.employeeid = pr.employeeid
INNER JOIN mastercode_table mc ON mc.codeid = rd.primaryskill
WHERE tm.project_id = 741
 AND tm.month_year = 'APR-2015' --months will be passed dynamically
GROUP BY pr.siteid,tm.month_year
ORDER BY SITE_STATUS DESC

SQL结果

SITE_STATUS  ACTUAL_HOURS   MONTH_YEAR
Onsite        307           APR-2015
Offshore      352           APR-2015

Answer 1

理想的输出并不是真正可以实现的，但是您可以使用以下命令：

$results = array();

foreach ($total_month_hours_result as $rows) {
    foreach ($rows as $data) {
        $results[$data['MONTH_YEAR']][$data['SITE_STATUS']] = $data['ACTUAL_HOURS'];
    }
}

要产生这个：

Array
(
    [APR-15] => Array
    (
        [Offshore] => 176,
        [Onsite]   => 180
    )
    // ...
)