Powershell比较对象返回错误结果

Question

我正在尝试使用以下命令比较2个文件夹的内容：

Compare-Object (Get-ChildItem C:\\compare -recurse) (Get-ChildItem J:\\compare -recurse) -Property FullName

这是我应该得到的结果：

FullName                       SideIndicator
--------                       -------------         
J:\compare\test1.txt           =>                     
C:\compare\install.msi         <=           
C:\compare\setup.exe           <=                    
C:\compare\subfolder\test3.txt <=     

这是我实际上得到的（我已经注意到两个文件夹中都存在对象，应该将它们从比较中排除）：

FullName                       SideIndicator
--------                       -------------
J:\compare\subfolder           => (exists in both folders)          
J:\compare\doc1.pdf            => (exists in both folders)           
J:\compare\doc2.pdf            => (exists in both folders)           
J:\compare\test1.txt           =>           
J:\compare\subfolder\test2.txt => (exists in both folders)           
C:\compare\subfolder           <= (exists in both folders)           
C:\compare\doc1.pdf            <= (exists in both folders)           
C:\compare\doc2.pdf            <= (exists in both folders)           
C:\compare\install.msi         <=           
C:\compare\setup.exe           <=           
C:\compare\subfolder\test2.txt <= (exists in both folders)           
C:\compare\subfolder\test3.txt <=  

为什么Powershell将两个文件夹中都存在的对象标记为不存在？ 好像我正在将-IncludeEqual与Compare-Object一起使用（不是），但是不是==侧指示器，而是得到了<=和=>。

Answer 1

您的比较应该是

Compare-Object `
  (Get-ChildItem C:\Compare -Recurse | Select-Object -ExpandProperty FullName | Split-Path -NoQualifier) `
  (Get-ChildItem J:\Compare -Recurse | Select-Object -ExpandProperty FullName | Split-Path -NoQualifier)

这是因为，正如@TessellatingHeckler指出的那样，两条路径之间的驱动器号（限定符）总是不同的，并且您想忽略该部分。