[英]Laravel 5 Can not get authenticated user from view
我正在尝试使用laravel身份验证服务。
问题是我可以成功注册新用户并重定向到成功页面。 但是,我无法在成功的页面内获得经过身份验证的用户。
下面显示了到目前为止所做的事情。
视图
<form class="form-horizontal" role="form" method="POST" action="/auth/register">
<input type="hidden" name="_token" value="{{ csrf_token() }}">
<div class="form-group">
<label class="col-md-4 control-label">User Name</label>
<div class="col-md-6">
<input type="text" class="form-control" name="username" value="{{ old('first_name') }}">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">E-Mail Address</label>
<div class="col-md-6">
<input type="email" class="form-control" name="email" value="{{ old('email') }}">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Password</label>
<div class="col-md-6">
<input type="password" class="form-control" name="password">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Confirm Password</label>
<div class="col-md-6">
<input type="password" class="form-control" name="password_confirmation">
</div>
</div>
<div class="form-group">
<div class="col-md-6 col-md-offset-4">
<button type="submit" class="btn btn-primary">
Register
</button>
</div>
</div>
</form>
用户模型(register_info)
/**
* The database table used by the model.
*
* @var string
*/
protected $table = 'register_info';
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = ['user_id','username', 'email', 'password','city'];
/**
* The attributes excluded from the model's JSON form.
*
* @var array
*/
protected $hidden = ['password', 'remember_token'];
/**
* The primary key for the model.
*
* @var string
*/
protected $primaryKey = 'user_id';
控制器:
class AuthController extends Controller
{
/*
|--------------------------------------------------------------------------
| Registration & Login Controller
|--------------------------------------------------------------------------
|
| This controller handles the registration of new users, as well as the
| authentication of existing users. By default, this controller uses
| a simple trait to add these behaviors. Why don't you explore it?
|
*/
use AuthenticatesAndRegistersUsers, ThrottlesLogins;
/**
* When a user is successfully authenticated
* they will be redirected to $redirectPath
*/
protected $redirectPath = 'manybotest';
/**
* When a user is not successfully authenticated
* they will be redirected to the $loginPath
*/
protected $loginPath = '/login';
/**
* Create a new authentication controller instance.
*
* @return void
*/
public function __construct()
{
$this->middleware('guest', ['except' => 'getLogout']);
}
/**
* Get a validator for an incoming registration request.
*
* @param array $data
* @return \Illuminate\Contracts\Validation\Validator
*
* 'email' => 'required|email|max:255|unique:register_info',
*/
protected function validator(array $data)
{
return Validator::make($data, [
'username' => 'required|max:255',
'password' => 'required|confirmed|min:6',
]);
}
/**
* Create a new user instance after a valid registration.
*
* @param array $data
* @return User
*/
protected function create(array $data)
{
return User::create([
'user_id' => uniqid('us'),
'username' => $data['username'],
'email' => $data['email'],
'password' => bcrypt($data['password'])
]);
}
}
路线:
Route::get('manybotest', function () {
$users = Auth::user();
return view('manybotest',compact('users'));
});
显示视图(manybotest.blade.php):
<?php
var_dump(Session::all());
var_dump(Auth::check());
var_dump(Auth::user());
var_dump(Auth::id());
var_dump($users);
?>
结果:
login_82e5d2c56bdd0811318f0cf078b78bfc => int 0//Session::all()
boolean false//Auth::check()
null//Auth::user()
int 0//Auth::id()
null//$users passed by routes
题:
我可以从会话中获取用户ID。 为什么无法获得经过身份验证的用户? 我还尝试检查laravel的内部代码,该用户已由laravel设置。
问题解决了:
主要问题是我的用户表ID是自定义的,而不是auto_increment ID。
在添加public $ incrementing = false之后 ; 对我的用户模型。 问题解决了。
class User extends Model implements AuthenticatableContract, CanResetPasswordContract
{
use Authenticatable, CanResetPassword;
public $incrementing = false;
/**
* The database table used by the model.
*
* @var string
*/
protected $table = 'register_info';
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = ['user_id','username', 'email', 'password','city'];
/**
* The attributes excluded from the model's JSON form.
*
* @var array
*/
protected $hidden = ['password', 'remember_token'];
/**
* The primary key for the model.
*
* @var string
*/
protected $primaryKey = 'user_id';
/**
* Get the bonding UserDetail
*
* @return UserDetail
*/
public function getUserDetail()
{
return $this->hasOne('App\Model\UserDetail','user_id','user_id');
}
}
问题分析:在laravel中,默认情况下,模型用户的ID设置为自动递增。 如果我们像我一样使用自定义的user_id。
/**
* Create a new user instance after a valid registration.
*
* @param array $data
* @return User
*/
protected function create(array $data)
{
return User::create([
'user_id' => uniqid('us'),
'username' => $data['username'],
'email' => $data['email'],
'password' => bcrypt($data['password'])
]);
}
返回的模型将包含一个自动增量ID。 我得到的总是0。因此,一个ID为0的User实例存储在laravel中。 当我调用Auth:user()时,我们将获得null而不是User实例。
{"user_id":"0","username":"xxxxx@gmail.com","password":"xxxxxxx"}
在添加public $ incrementing = false之后 ; 对我的用户模型。 我可以使用我定义的ID正确获取用户实例。
{"user_id":"us55f7e7afbe87f","username":"xxxxx@gmail.com","password":"xxxxxxx"}
希望这会有所帮助。
谢谢大家的帮助。
您必须将Guard
注入并Register
到构造函数中。
use Illuminate\Contracts\Auth\Guard;
use Illuminate\Contracts\Auth\Registrar;
class AuthController extends Controller
{
public function __construct(Guard $auth, Registrar $registrar)
{
parent::__construct();
$this->auth = $auth;
$this->registrar = $registrar;
$this->middleware('guest', ['except' => 'getLogout']);
}
如果查看AuthenticatesAndRegistersUsers ,则可以看到在postRegister
方法中, login
是在$this->auth
上调用的。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.