[英]Using user input to call an integer
我是编码的初学者,我正在尝试创建一个简单的程序,当读者键入他们的姓名时,该程序将显示他们欠的钱。 我当时正在考虑使用Scanner
, next(String)
和int
。
import java.util.Scanner;
public class moneyLender {
//This program will ask for reader input of their name and then will output how much
//they owe me. (The amount they owe is already in the database)
public static void main(String[] args) {
int John = 5; // John owes me 5 dollars
int Kyle = 7; // Kyle owes me 7 dollars
//Asking for reader input of their name
Scanner reader = new Scanner(System.in);
System.out.print("Please enter in your first name:");
String name = reader.next();
//my goal is to have the same effect as System.out.println("You owe me " + John);
System.out.println("You owe me: " + name) // but not John as a string but John
// as the integer 5
//Basically, i want to use a string to call an integer variable with
//the same value as the string.
}
}
作为一个初学者,您可能想使用一个简单的HashMap
,它将这些映射存储为键,值对。 Key
将是name
, value
将是money
。 这是示例:
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class moneyLender {
public static void main(String[] args) {
Map<String, Integer> map = new HashMap<String, Integer>();
map.put("John", 5);
map.put("Kyle", 7);
Scanner reader = new Scanner(System.in);
System.out.print("Please enter in your first name:");
String name = reader.next();
System.out.println("You owe me: " + map.get(name)); //
}
}
输出:
请输入您的名字:约翰
你欠我:5
如果要以字符串形式读取用户输入,则最好使用nextLine()方法。
您还希望创建一个使用String参数(即名称)并返回所欠金额的方法。
public int moneyOwed(String name){
switch(name){
case "Kyle": return 5;
case "John": return 7;
}
}
public static void main(String[] args) {
int John = 5; // John owes me 5 dollars
int Kyle = 7; // Kyle owes me 7 dollars
Scanner reader = new Scanner(System.in);
System.out.print("Please enter in your first name:");
String name = reader.nextLine();
System.out.println(name +" owes me " + moneyOwed(name) + " dollars");
}
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