[英]ns1: C# deserialization issue
以下是用于获取ns1:问题的测试代码,我总是得到一个没有任何内容的对象。
如果删除两个[XmlType]
和[XmlRoot]
则会出错。
我确信可能已经有人遇到了可能找不到正确的搜索词的问题,
完全希望这是一件简单的事情。
[XmlType(AnonymousType = true, Namespace = "http://itaintworking.com/test/")]
[XmlRoot(Namespace = "http://itaintworking.com/test/", IsNullable = false)]
public class Clients
{
public string clientName { get; set; }
public addressDetails addressDetails { get; set; }
}
public class addressDetails
{
public int addressId { get; set; }
}
[Test(Description = "Serialization Exception")]
public void CheckDeserializer()
{
var strXml =
"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?><ns1:Clients xmlns:ns1=\"http://itaintworking.com/test/\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" ><clientName>hello</clientName><addressDetails><addressId>98989</addressId></addressDetails></ns1:Clients>";
var x = XmlSerializer<Clients>.Deserialize(strXml);
Assert.IsNotNull(x);
}
我正在使用一些使用泛型的代码,还有另一种方法默认为UTF8编码,而xmlReaderSetting为null。
/// <summary>
/// Deserializes a XML string into an object
/// </summary>
/// <param name="xml">The XML string to deserialize</param>
/// <param name="encoding">The encoding</param>
/// <param name="settings">XML serialization settings. <see cref="System.Xml.XmlReaderSettings"/></param>
/// <returns>An object of type <c>T</c></returns>
public static T Deserialize(string xml, Encoding encoding, XmlReaderSettings settings)
{
if (string.IsNullOrEmpty(xml))
throw new ArgumentException("XML cannot be null or empty", "xml");
var xmlSerializer = new XmlSerializer(typeof(T));
using (var memoryStream = new MemoryStream(encoding.GetBytes(xml)))
{
using (var xmlReader = XmlReader.Create(memoryStream, settings))
{
return (T)xmlSerializer.Deserialize(xmlReader);
}
}
}
目前尚不清楚您将如何解决此问题。
由于它目前矗立在XML中, clientName
和addressDetails
的内元素Clients
元素不在同一个命名空间。 因此,一种解决方法是:
[XmlType(AnonymousType = true, Namespace = "http://itaintworking.com/test/")]
[XmlRoot(Namespace = "http://itaintworking.com/test/", IsNullable = false)]
public class Clients
{
[XmlElement(Namespace="")]
public string clientName { get; set; }
[XmlElement(Namespace = "")]
public addressDetails addressDetails { get; set; }
}
另一个解决方法可能是更改XML中的名称空间:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ns1:Clients xmlns:ns1="http://itaintworking.com/test/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<ns1:clientName>hello</ns1:clientName>
<ns1:addressDetails>
<ns1:addressId>98989</ns1:addressId>
</ns1:addressDetails>
</ns1:Clients>
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