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[英]Regex - Find a 8 letters word with either number/alphabets/both and ending with .php
[英]PHP regex find word (even with double letters) then replace it
我正在使用PHP创建一个字符串过滤器。 我需要用其他单词替换一些单词,因此我正在使用str_replace()函数,如下所示:
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array("fruits", "vegetables", "fiber");
$yummy = array("pizza", "beer", "ice cream");
$newphrase = str_replace($healthy, $yummy, $phrase);
// echo -> "You should eat pizza, beer, and ice cream every day.";
到目前为止还算不错,但是即使它们包含几个这样的字母,我也需要替换它们:
$phrase = "You should eat fruuits, vegetaaables, and fiiibeeer every day.";
我发现此示例删除字符串中的双字母:
$string = preg_replace('/(\w)\1+/', '$1', $phrase);
但是,如果我将此示例应用于我的字符串,则所有带有双字母的单词都将被更改...例如,“ Google”将变为“ Gogle”,而我不希望那样。
有任何想法吗 ? 谢谢!
我会做这样的事情
$phrase = "You should eat suck, sck, and suuucky every day.";
$healthy = 's+u*c+k+';
$yummy = 'luck';
$newphrase = preg_replace('/' . $healthy . '/', $yummy, $phrase);
echo $newphrase;
输出:
You should eat luck, luck, and lucky every day.
+
是量词,表示一个或多个前一个字符。 *
是零个或多个量词,表示该字符不必存在,但如果存在任何数量的该字符,则可以存在。
演示: https : //regex101.com/r/sN5sZ6/1
同样,应该使用ass
词边界,因为您不想替换class
等。https: //regex101.com/r/oM4wY1/2 Kinda却变成了一条蜿蜒的路。
如果您想要特定的单词,则可以在preg_replace
使用多种模式。
对于您的示例,您可以使用以下多个模式:
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$patterns = array("/fru+its/", "/vegeta+bles/", "/fi+be+r/");
$yummy = array("pizza", "beer", "ice cream");
$newphrase = preg_replace($patterns, $yummy, $phrase);
如果您只想检测fruits
, vegetables
和fiber
,则可以使用:
$patterns = array("f+r+u+i+t+s+", "v+e+g+e+t+a+b+l+e+s+", "f+i+b+e+r+");
工作实例
$word =array('fiber', 'milk', 'nuts'); // words to scan for
$phrase = "You should eat fibeeer, nuuuuts, and milkkk every day."; //phrase
$filter = array(); // array of dynamicly generated filters
foreach($word as $name){ // loop for filter generating
$temp = str_split($name);
$temp = implode('{1,}', $temp). '{1,}';
$filter[$name] = $temp;
}
$phraseTable = explode(' ', $phrase); // getting phrase into an array
foreach($phraseTable as &$data){ // scanning phrase
foreach($filter as $name => $value){
if( preg_match( '/'.$value.'[,.]?/', $data)){
$data = $name;
}
}
}
$phraseScanned = implode(' ', $phraseTable); // imploding formatted phrase
echo $phraseScanned; // echo result
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